$\sqrt{8 x^{12} y^{7} } = \sqrt{8} \sqrt{x^{12}} \sqrt{ y^{6}*y } =\sqrt{4} \sqrt{2} \sqrt{(x^{6} )^{2} } \sqrt{ (y^{3})^{2}} \sqrt{y}=2 \sqrt{2} x^{6} y^{3} \sqrt{y} 
$

<span>I hope it helps you :)</span>

8 0

2 years ago

Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to f

Paraphin [41]

Answer:

Step-by-step explanation:

The normal distribution curve standard is bell shaped having mean =0 and std devition =1.

This is symmetrical about the y axis i.e. mean. More than 99% of the area under the curve lie between z=-3 to z=3

To find the area to the right of z =0.05 is equivalent to

calculating the

Probability that Z >0.05

= P(Z>0.05)

=0.5-0.0199

=0.4801

(the sketch is attached)

8 0

2 years ago

Suppose James has a credit card with a balance of $4289. Each month, the credit card company charges 5% interest. James pays off

Sidana [21]

The answer is exponential growth

6 0

3 years ago

Find the surface area of the pyramid.

Taya2010 [7]

460 cm squared
Hope that helped XD

7 0

3 years ago