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1 year ago

Find the length of the missing side. the triangle is not drawn to scale. 6, 8, 90

Mathematics

2 answers:

Veseljchak [2.6K]1 year ago

8 0

Answer:

I think A should be right but I'm not sure.

Step-by-step explanation:

Hope this helps

Monica [59]1 year ago

7 0

Answer:

A. 10

Step-by-step explanation: This is the Pythagorean theorem

$c^2=a^2+b^2$

c is the hypotenuse so a and b are going to be the vertical and horizontal sides.

$c^2=6^2+8^2\\
c^2=36+64\\
c^2=100\\
c=10$

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A dot plot titled Number of classes going from 3 to 7. 3 has 5 dots, 4 has 6 dots, 5 has 5 dots, 6 has 4 dots, 7 has 3 dots.

Alex777 [14]

Answer:

Skewed right. btw thx have a nice day!!!!!!!!!!!!!!!

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Daca a + b = 20 si b + c = 30 ,calculati 3 . a + 7 . b + 4 . c ( Dau coroana la cine ma ajuta )

Oduvanchick [21]

It is given that

a+b=20 -------------------- (1)

b+c=30 -----------------------(2)

We have to calculate

3 a + 4 b +7 c

Now multiplying equation(1 )by 3,we get

3 a+ 3 b=60 ----------------------------------(3)

and Multiplying equation( 2) by 4,we get

4 b + 4 c=120 -----------------------------------(4)

Adding expression (3) and (4),we get i.e left hand side of 3 to left hand side of 4 and right hand side of 3 to right hand side of 4.

3 a+ 3 b+ 4 b+ 4 c=60+120

Adding like terms, we get

3 a+ 7 b+ 4 c =180, Which is the required solution.

4 0

2 years ago

I don't know what to do

Debora [2.8K]

This is easy go on khan academy an look up how to find the y coordinate

7 0

3 years ago

Read 2 more answers

What is a formula for the nth term of the given sequence? 15, 24, 33

KatRina [158]

Answer:

The nth terms: 15,24,33,42,51,60,69,78,87,96,105...

Step-by-step explanation:

The nth term of an arithmetic sequence is given by an = a + (n – 1)d. So, to find the nth term, substitute the given values a = 2 and d = 3 into the formula

5 0

2 years ago

Evaluate Dx / ^ 9-8x - x2^

Solnce55 [7]

It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for $\sqrt x$ .

In that case, you want to find the antiderivative,

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}$

Complete the square in the denominator:

$9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2$

Now substitute $x+4=5\sin y$ , so that $\mathrm dx=5\cos y\,\mathrm dy$ . Then

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy$

which simplifies to

$\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy$

Now, recall that $\sqrt{x^2}=|x|$ . But we want the substitution we made to be reversible, so that

$x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)$

which implies that $-\dfrac\pi2\le y\le\dfrac\pi2$ . (This is the range of the inverse sine function.)

Under these conditions, we have $\cos y\ge0$ , which lets us reduce $\sqrt{\cos^2y}=|\cos y|=\cos y$ . Finally,

$\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C$

and back-substituting to get this in terms of $x$ yields

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C$

4 0

2 years ago