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Maslowich
3 years ago
10

Please help me with part b of number 16.

Mathematics
1 answer:
natka813 [3]3 years ago
7 0
You want to find the time (x) when the distance from desitnation is 0:

d = 0,

d(x) = 1375 - 110x
0 = 1375 - 110x
110x = 1375
x = 1375/110
<u>x = 12.5 hrs</u>
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Which of the following is the equation for the graph shown?a. x^2/144+y^2/95=1b. x^2/144-y^2/95=1c. x^2/95+y^2/144=1d. x^2/95-y^
Andrews [41]

e follSOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the general equation of an ellipse

\frac{\mleft(x-h\mright)^2}{a^2}+\frac{(y-h)^2}{b^2^{}}=1

STEP 2: Identify the parameters

the length of the major axis is 2a

the length of the minor axis is 2b

\begin{gathered} 2a=24,a=\frac{24}{2}=12 \\ 2b=20,b=\frac{20}{2}=10 \end{gathered}

STEP 3: Get the equation of the ellipse

\begin{gathered} By\text{ substitution,} \\ \frac{(x-h)^2}{a^2}+\frac{(y-h)^2}{b^2}=1 \\ \frac{(x-0)^2}{12^2}+\frac{(y-0)^2}{10^2}=1=\frac{x^2}{144}+\frac{y^2}{100}=1 \end{gathered}

STEP 4: Pick the nearest equation from the options,

Hence, the equation of the ellipse in the image is given as:

\frac{x^2}{144}+\frac{y^2}{95}=1

OPTION A

8 0
1 year ago
Write 0.09 as a simplified fraction
Illusion [34]
9/100, let me know if this helps.
4 0
3 years ago
Let f(x) = 3x + 2 and g(x) = 4–5x. Find f(x) + g(x)
Vadim26 [7]

Answer:

-2x + 6

Step-by-step explanation:

Step 1: Define

f(x) = 3x + 2

g(x) = 4 - 5x

Step 2: Find f(x) + g(x)

3x + 2 + 4 - 5x

-2x + 6

3 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!! I WILL GIVE ALL THESE POINTS
WINSTONCH [101]
<h2>Answer and Explanation to questions 13,14,15</h2>

13) \mathbf{\overline{XY}\cong\overline{CD}}        as given in the question.

14) \mathbf{\overline{XY}\cong\overline{YZ}}          Since Y is the midpoint of XZ. So, Y will divide XZ in equal halves into XY and YZ.

15) \mathbf{\overline{CD}\cong\overline{YZ}}

\because\overline{\textrm{XY}}\cong\overline{\textrm{CD}} and \overline{\textrm{XY}}\cong\overline{\textrm{YZ}} . So, \overline{\textrm{CD}}\cong\overline{\textrm{YZ}}

<h2>Answer and Explanation to questions 16,17,18</h2>

∠3 is supplementary to ∠1 means: ∠3 + ∠1 = 180°

And, according to figure ∠1 + ∠2 = 180° as ∠1 and ∠2 form a straight line.

∠3 + ∠1 = 180°    .............(i)

∠1 + ∠2 = 180°    .............(ii)

subtracting equation (i) and (ii) will give ∠3 = ∠2   ..........(iii)

15) ∠3 is supplementary to ∠1                        as given in the question

16) ∠2 is supplementary to ∠1                        as shown be equation (ii)

18) ∠3 ≅ ∠2                                                      as shown by equation (iii)

<h2>Answer and Explanation to questions 19</h2>

∠3 and ∠4 form a straight line. Therefore, ∠3 + ∠4 = 180°   .......(i)

∠4 and ∠5 form a straight line. Therefore, ∠4 + ∠5 = 180°   .......(ii)

subtracting equation (i) and (ii)

∠3 + ∠4 - (∠4 + ∠5) = 180°-(180°)

∠3 + ∠4 - ∠4 - ∠5 = 180°-180°

∠3 - ∠5 = 0

∴ ∠3 = ∠5     (Hence Proved)

4 0
3 years ago
Find the volume v of the described solid s.a right circular cone with height 6h and base radius 4r
guapka [62]
Use this formula=1/3πr2h
8 0
3 years ago
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