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The correct answer is the second option. These deposits are a result of solutes becoming un-dissolved from a solution. These solutes are from the water or liquid that you are boiling in the kettle. As you boil a liquid mixture, it is possible that some of the solutes would precipitate because the solubility of such solute is lowered due to the increase in the temperature. Most solubility of solid solutes are related to temperature inversely. So, as the temperature increases, the solubility would decrease. Solubility is the amount of a solute that can be completely dissolved in a certain amount of solvent.
Answer:
Removing O₂, means removing one of the reactants and the system would counteract this effect by producing more O₂, thereby shifting the equilibrium position to the left and favouring the backward reaction.
Explanation:
The principle that explains how changes in temperature, Concentration and Pressure of reactants or products of a reaction at equilibrium affect the equilibrium position of the reaction is the Le Chatelier's principle.
The Principle explains that a system/process if a system/process which is at equilibrium is disturbed/perturbed/constrained by one or more changes (in concentration, pressure or temperature), the system would shift the equilibrium position to counteract the effects of this change.
Removing O₂, means removing one of the reactants (changing its concentration) and the system would counteract this effect by producing more O₂, thereby shifting the equilibrium position to the left and favouring the backward reaction.
Answer:
Moles added = 0.0722 moles
Mass added = 2.3104 g
Explanation:
Given:
Pressure = 640.0 torr
The conversion of P(torr) to P(atm) is shown below:
So,
Pressure = 640 / 760 atm = 0.8421 atm
Temperature = 25.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (25.0 + 273.15) K = 298.15 K
Volume = 42.9 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
0.8421 atm × 42.9 L = n × 0.0821 L.atm/K.mol × 298.15 K
⇒n = 1.4759 moles
Some new moles have been added and the volume has increased to 45.0 L
Using Avogadro's law
Given ,
V₁ = 42.9 L
V₂ = 45.0 L
n₁ = 1.4759 moles
n₂ = ?
Using above equation as:
n₂ = 1.5481 moles
Moles added = n₂ - n₁ = 1.5481 moles - 1.4759 moles = 0.0722 moles
Molar mass of oxygen gas = 32 g/mol
So, Mass = Moles*Molar mass = 0.0722 * 32 g = 2.3104 g
<u>Moles added = 0.0722 moles</u>
<u>Mass added = 2.3104 g</u>
Answer:
For an element, the molar mass is the mass of 1 mol of atoms of that element; for a covalent molecular compound, it is the mass of 1 mol of molecules of that compound; for an ionic compound, it is the mass of 1 mol of formula units.
Explanation: