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Paraphin [41]
4 years ago
6

What is the x-coordinate of the function below when the y-coordinate is 0?(0,5) (2,-5)

Chemistry
1 answer:
maria [59]4 years ago
4 0

The equation of the function is assumed to be a straight line is of the form,

y= mx+c,  where  m,c

are the gradient and the y intercept respectively.

The gradient is computed using the formula for the gradient, i.e

m=\frac{y_2-y_1}{x_2-x_1} =  \frac{-5-5}{2-0} = -5.

The equation of the line is,

y= -5x+c\\=>5=-5(0)+c\\=> c= 5


The equation of the function is ,

y = -5x+5..

The value of the x-coordinate when the y coordinate is 0 is found as shown below.

0=-5x+5\\=>x=1\\.

so the x-coordinate is 1.

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Use the equation editor or "Insert Chemistry - WIRIS editor" to write the balanced molecular chemical equation for the reaction
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Answer:

The balanced molecular equation  for the reaction :

Cu(NO_3)_2(aq)+K_2CO_3(aq)\rightarrow CuCO_3(s)+2KNO_3(aq)

Explanation:

The reaction between copper(II) nitrate  and potassium carbonate gives solid precipitate of copper(II) carbonate and aqueous solution of potassium nitrate.

Cu(NO_3)_2(aq)+K_2CO_3(aq)\rightarrow CuCO_3(s)+2KNO_3(aq)

According to reaction, 1 mole of copper(II) nitrate reacts with 1 mole of potassium carbonate to give 1 mole of copper(II) carbonate and 2 moles of potassium nitrate,

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Both 1,2−dihydronaphthalene and 1,4−dihydronaphthalene may be selectively hydrogenated to 1,2,3,4−tetrahydronaphthalene. One of
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Answer:

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1,2-dihydro = 101 kJ·mol⁻¹

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In 1,2-dihydronaphthalene, the 3,4-double bond is conjugated with the benzene ring.

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1,2-Dihydronaphthalene is at a lower energy level because of this stabilization.

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Calculate the pH of a solution in which one normal adult dose of aspirin (640 mg ) is dissolved in 10 ounces of water. Express y
d1i1m1o1n [39]

The pH of the solution in which one normal adult dose aspirin is dissolved is :  2.7

Given data :

mass of aspirin = 640 mg = 0.640 g

volume of water = 10 ounces = 0.295735 L

molar mass of aspirin = 180.16 g/mol

moles of aspirin = mass / molar mass = 0.00355 mol

<h3>Determine the pH of the solution </h3>

First step : <u>calculate the concentration of aspirin</u>

= moles of Aspirin / volume of water

= 0.00355 / 0.295735

= 0.012 M

Given that pKa of Aspirin = 3.5

pKa = -logKa

therefore ; Ka = 10^{-3.5} = 3.162 * 10^{-4}

From the Ice table

3.162 * 10^{-4} = \frac{x + H^+}{[aspirin]}  = \frac{x^{2} }{0.012-x}

given that the value of Ka is small we will ignore -x

x² = 3.162 * 10^{-4} * 0.012

x = 1.948 * 10^{-3}  

Therefore

[ H⁺ ] = 1.948 * 10^{-3}

given that

pH = - Log [ H⁺ ]

     = - ( -3 + log 1.948 )

     = 2.71 ≈ 2.7

Hence we can conclude that The pH of the solution in which one normal adult dose aspirin is dissolved is :  2.7

Learn more about Aspirin : brainly.com/question/2070753

4 0
2 years ago
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