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elena55 [62]
3 years ago
13

What is the final concentration if a 50.0 mL sample of a 15% H2SO4 solution is added to water to give a final volume of 250 mL?

Chemistry
1 answer:
Anna007 [38]3 years ago
4 0

Answer:

The answer to your question is 3% H2SO4 solution

Explanation:

Data

Concentration 2 = C₂ = ?

Concentration 1 = C₁ = 15 %

Volume 1 = V₁ = 50 ml

Volume 2 = V₂ = 250 ml

Formula

             C₁V₁  = C₂V₂

Solve for C₂

             C₂ = C₁V₁ / V₂

Substitution

             C₂ = (15)(50) / 250

Simplification and result

             C₂  = 3 %

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Calculate the mass of nitric acid required to make a 250mL solution with 2.40 ph
meriva

The mass of nitric acid required to make the given solution is 0.0627 g.

The given parameters:

  • <em>Volume of the acid, V = 250 mL</em>
  • <em>pH of the acid, = 2.4</em>

The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;

H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 0.00398

The molarity of the nitric acid is calculated as follows;

=  0.00398 \ H^+ \times \frac{1 \ M \ HNO_3}{1 \ H^+} \\\\= 0.00398 \ M

The number of moles of the nitric acid is calculated as follows;

moles = M\times L\\\\moles = 0.00398\ M \ \times \ \frac{250 \ mL}{1000} \\\\moles = 9.95 \times 10^{-4} \ mol.

The molar mass of nitric acid is calculated as;

HNO_3 = (1) \ + (14) \ + (16 \times 3) = 63 \ g/mol

The mass of the nitric acid contained in the calculated number of moles is calculated as;

mass = moles\  \times \ molar \ mass\\\\mass = 9.95\times 10^{-4} \ mol. \ \times \ 63 \ g/mol\\\\mass = 0.0627 \ g

Thus, the mass of nitric acid required to make the given solution is 0.0627 g.

Learn more about molarity of acids here: brainly.com/question/13864682

3 0
2 years ago
Alkanes do not have geometric isomers because the carbon atoms in their carbon-carbon bonds are _____.
Mariana [72]
The word that best fits the underlined in the sentence is "free-to-rotate." The carbon atoms in their carbon bonds are free to rotate since alkanes do not have geometric isomers. They only have single bonds and the most common example of which are trans molecules. 
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2 years ago
Read 2 more answers
Im hvaing a hard time getting the right answer
Tanya [424]

Answer:

V=23.9mL

Explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

n=2.49g*\frac{1mol}{125.55 g}=0.0198mol

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

M=\frac{n}{V}\\\\V=\frac{n}{M}

By plugging in the moles and molarity, we obtain:

V=\frac{0.0198mol}{0.830mol/L}=0.0239L

Which in mL is:

V=0.0239L*\frac{1000mL}{1L}\\\\V=23.9mL

Best regards!

6 0
3 years ago
What is a photon?
Anika [276]
The Answer should be A Light particle
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2 years ago
Suppose you have a mixture of copper sulfate (CuSO4) and azulene (C10H8, you may wish to know the structure of azulene). Both co
iVinArrow [24]

Answer:

Aqueous layer (1 M HCI)

Explanation:

First of us I want to remind you of the cliché in chemistry that like dissolves like. In solvent extraction, a mixture is dissolved in a system consisting of two immiscible solvents. One layer is organic while the other layer is aqueous.

Polar substances partition in the aqueous layer while nonpolar substances partition in the organic layer.

Since Copper sulfate is ionic, we will find it in the aqueous layer according to the old chemistry cliche.

3 0
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