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elena55 [62]
3 years ago
13

What is the final concentration if a 50.0 mL sample of a 15% H2SO4 solution is added to water to give a final volume of 250 mL?

Chemistry
1 answer:
Anna007 [38]3 years ago
4 0

Answer:

The answer to your question is 3% H2SO4 solution

Explanation:

Data

Concentration 2 = C₂ = ?

Concentration 1 = C₁ = 15 %

Volume 1 = V₁ = 50 ml

Volume 2 = V₂ = 250 ml

Formula

             C₁V₁  = C₂V₂

Solve for C₂

             C₂ = C₁V₁ / V₂

Substitution

             C₂ = (15)(50) / 250

Simplification and result

             C₂  = 3 %

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NH3 +<br>H2SO4 → __(NH4)2SO4​
Zielflug [23.3K]

Answer:

This is not a balanced equation

Explanation:

Let's make it a balanced equation.

2 NH3 + H2So4 = (NH4)2So4

Glad I could help!!

8 0
3 years ago
When a barium atom loses two electrons what charge does it have
Darya [45]

Answer:

It becomes a positive ion and its radius decreases

Explanation:

As per the Octet rule, Barium has 2 electrons in its outermost shell. When it loses the two electron it gains two positive charge i.e Ba2+. As the barium loses the two electron from its outermost shell, the outermost shell becomes vacant and thus is no more considered as a part of atomic geometry of the barium atom and since the outermost shell is considered negligible the radius of barium atom reduces automatically.  

6 0
3 years ago
How many moles of oxygen (O2) are present in 33.6 L of the gas at 1 atm and 0°C?
maw [93]

Answer: 1.5

Explanation:

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3 0
3 years ago
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Answer:

2y+3m2= 2ym3

Explanation:

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6 0
2 years ago
What are the concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium when 18.8 g of Cu(NO3)2 is added to 1.0 L of a 0.800 M s
Svetllana [295]

Answer:

Explanation:

Cu(NO₃)₂ + 4NH₃ = Cu(NH₃)₄²⁺  + 2 NO₃⁻

187.5 gm      4M           1 M

187.5 gm reacts with 4 M ammonia

18.8 g     reacts with  .4 M ammonia

ammonia remaining left after reaction

= .8 M - .4 M = .4 M .

187.5 gm reacts with 4 M ammonia   to form 1 M Cu(NH₃)₄²⁺

18.8 g reacts with .4 M ammonia  to form 0.1 M Cu(NH₃)₄²⁺  

At equilibrium , the concentration of Cu²⁺ will be zero .

concentration of ammonia will be .4 M

concentration of  Cu(NH₃)₄²⁺ formed will be 0.1 M

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3 years ago
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