The expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
From the question,
We are to factorize the expression (h+2k)²+4k²-h² completely
The expression can be factorized as shown below
(h+2k)²+4k²-h² becomes
(h+2k)² + 2²k²-h²
(h+2k)² + (2k)²-h²
Using difference of two squares
The expression (2k)²-h² = (2k+h)(2k-h)
Then,
(h+2k)² + (2k)²-h² becomes
(h+2k)² + (2k +h)(2k-h)
This can be written as
(h+2k)² + (h +2k)(2k-h)
Now,
Factorizing, we get
(h +2k)[(h+2k) + (2k-h)]
Hence, the expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
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Answer:
19,167
Step-by-step explanation:
Laura purchased a new vehicle for 27,382
She made a down payment of 30%
27,382×30/100
= 27,382×0.3
= 8,214.6
27382-8214.6
= 19,167
Hence Laura financed 19,167
Answer:
The answer is e
Step-by-step explanation: I calculated the percent and none of these match up 6% of 4000 is 240
2(x+3)= 3x-1
2x+6=3x-1
X=7
Therefore
YM = 7+3= 10
And by definition of midpoint YM=MZ so MZ=10
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