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2 years ago

Find three consecutive odd integers whose sum is-213.

Mathematics

2 answers:

Alex2 years ago

5 0

Answer:

first odd number be x = - 73

second odd number be x + 2 = (- 73 + 2) = - 71

third odd number be x + 4 = (- 73 + 4) = - 69

Step-by-step explanation:

let the first odd number be x

second odd number be x + 2

third odd number be x + 4

Now, three consecutive odd integers whose sum is - 213.

i.e.,

(x) + (x + 2) + (x + 4) = - 213

Then,

(x) + (x + 2) + (x + 4) = - 213

x + x + 2 + x + 4 = - 213

3x + 6 = - 213

3x = - 213 - 6

3x = - 219

x = - 219/3

x = - 73

Thus, The value of x is - 73

Here,

first odd number be x = - 73

second odd number be x + 2 = (- 73 + 2) = - 71

third odd number be x + 4 = (- 73 + 4) = - 69

(x) + (x + 2) + (x + 4) = - 213

(- 73) + (- 73 + 2) + (- 73 + 4) = - 213

(- 73) + (- 71) + (- 69) = - 213

- 73 - 71 - 69 = - 213

- 213 = - 213

Hence, L.H.S = R.H.S

<u>-TheUnknown</u><u>Scientist</u>

Degger [83]2 years ago

4 0

X + x + 2 + x + 4 = -213
3x + 6 = -213
3x = -219
x = -73
-73 + 2 = -71
-73 + 4 = -69
Solution: -73, -71, -69

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The price of a watch was increased by 20% to £144. What was the price before the increase?

hammer [34]

Answer:

120 pounds

Step-by-step explanation:

Since the new cost is 144 pounds and this is 20% more, this is 120% of the original price. Remember 100+20 = 120. To find the original price set up a proportion with these values:

$\frac{144}{x}=\frac{120}{100}$

Solve for the original price by cross multiplying numerator with denominator.

x(120) = 144(100)

120x = 14400

x= 120 pounds

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3 years ago

Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,

Aleksandr-060686 [28]

Answer:

The expected value of the points earned on a single roll in this game is $\dfrac{1}{6} = 0.1667$ .

Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is $\dfrac{1}{6}$ .

Numbers on the dice (X) P(X)

+1 $\frac{1}{6}$

+2 $\frac{1}{6}$

+3 $\frac{1}{6}$

-4 $\frac{1}{6}$

+5 $\frac{1}{6}$

-6 $\frac{1}{6}$

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X) = $\sum X \times P(X)$

= $(+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}$

= $\frac{1}{6} + \frac{2}{6} + \frac{3}{6} - \frac{4}{6} + \frac{5}{6} - \frac{6}{6}$

= $\frac{1+2+3-4+5-6}{6}$

= $\frac{11-10}{6}= \frac{1}{6}$

Hence, the expected value of the points earned on a single roll in this game is $\frac{1}{6} = 0.1667$ .

4 0

3 years ago

BRAINLIEST TO CORRECT PLEASE HURRY

kicyunya [14]

Answer:

-1, 9/18, 0.5

Step-by-step explanation:

I put into decimials

-1 = -1

9/18 = 0.5

1 8/16 = 1.5

(I think that is IXL, good luck!)

3 0

2 years ago

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A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

3 years ago

A surfboard has an original price of $259. It is on sale for 55% off the original price.

grin007 [14]

I'm not sure what answer you need for this question?
original price: 259
sale: 55% off
55%=0.55
so 259×0.55=142.45
142.45 is the 55% of the original price
259－142.45=116.55
116.55 is the price after sale.
hope this would help. (*^ω^*)/

5 0

3 years ago

Read 2 more answers