In my work I used t=trains and m=minutes:
30+30= 60m/2t
<span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
Total= 720m/24t
1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30= 4 o' clock
Total= 372m/12t
24t+12t= 36t
The answer is:
36 trains in total</span>
The length of CD is 7-3=4.
Therefore, if we dilate by a scale factor of 3, the length is 4(3) = 12
Answer:
a. 2
c. efx = 20 = 2.22
x. 9
b.1/2×20 = 10
Step-by-step explanation:
it is 2 because it has the highest frequency