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creativ13 [48]
3 years ago
7

Simplifica (3x +5) (x -8)

Mathematics
1 answer:
Marrrta [24]3 years ago
4 0
Um do you want that simplified you need to add more information or something
You might be interested in
Find an equation for the line parallel to 3y+6X=6 and goes through the point (-3,-7) please write in y=mx+b
seropon [69]

Answer: y=-6x-25

Step-by-step explanation:

Find slope of original line by solving for y

3y+6x=6

y+6x=2

y = -6x+2 <--- we have found the slope is -6

Using y-y1 = m (x-x1) find the equation for the parallel line:

y-(-7)= -6(x-(-3)) <--- plug in the point coordinates and slope into the equation and solve for y

y+7=-6x-18

y=-6x-25

5 0
2 years ago
Help meeeeeeeeeeeeeee pls
WITCHER [35]

Answer:

Area = 15.36 ft

Step-by-step explanation:

First find the area of the dotted line triangle using the formula: base x height x 1/2, which would be 1.2ft x 12.8 x 1/2 = 7.68ft.

Next, add another triangle at the top, mirroring the shown triangle, of the parallelogram.

Then, find the area of the shape as though it were a rectangle. (base x height) - 2.4 x 12.8 = 30.72.

Next, multiply the area of the invisible triangle by 2, 7.68 x 2 = 15.36ft

and Finally, subtract the area of the rectangle shape of the the sum of the two invisible triangles, 30.72 - 15.36 = 15.36ft

The area of the parallelogram is 15.36 ft.

5 0
2 years ago
Write an equation for a quadratic function that has x intercepts (-3, 0) and (5, 0)
Blizzard [7]

Answer:

One possible equation is f(x) = (x + 3)\, (x - 5), which is equivalent to f(x) = x^{2} - 2\, x - 15.

Step-by-step explanation:

The factor theorem states that if x = x_{0}  (where x_{0} is a constant) is a root of a function, (x - x_{0}) would be a factor of that function.

The question states that (-3,\, 0) and (5,\, 0) are x-intercepts of this function. In other words, x = -3 and x = 5 would both set the value of this quadratic function to 0. Thus, x = -3\! and x = 5\! would be two roots of this function.

By the factor theorem, (x - (-3)) and (x - 5) would be two factors of this function.

Because the function in this question is quadratic, (x - (-3)) and (x - 5) would be the only two factors of this function. In other words, for some constant a (a \ne 0):

f(x) = a\, (x - (-3))\, (x - 5).

Simplify to obtain:

f(x) = a\, (x + 3)\, (x - 5).

Expand this expression to obtain:

f(x) = a\, (x^{2} - 2\, x - 15).

(Quadratic functions are polynomials of degree two. If this function has any factor other than (x - (-3)) and (x - 5), expanding the expression would give a polynomial of degree at least three- not quadratic.)

Every non-zero value of a corresponds to a distinct quadratic function with x-intercepts (-3,\, 0) and (5,\, 0). For example, with a = 1:

f(x) = (x + 3)\, (x - 5), or equivalently,

f(x) = x^{2} - 2\, x - 15.

6 0
2 years ago
Describe how you made a line plot in this lesson
serious [3.7K]
What lesson are we talking about I will be happy to help.
5 0
3 years ago
Read 2 more answers
The points A(3, 4), B(3, -2), C(-5, -2), and D(-5, 4) form rectangle ABCD. Which point is halfway between A and B?
Dmitriy789 [7]
 Answer:  " (3,1)  is the point that is halfway between <em>A</em> and <em>B</em>. " 
__________________________________________________
Explanation:
__________________________________________________
We know that there is a "straight line segment" along the y-axis between
 "point A"  and "point B" ;  since, we are given that: 
___________________________________________
 1)  Points A, B, C, and D form a rectangle;  AND:
 
 2) We are given the coordinates for each of the 4 (FOUR points); AND:
 
 3) The coordinates of  "Point A" (3,4)  and "Point B" (3, -2) ; have the same "x-coordinate" value.
________________________________________________
  We are asked to find the point that is "half-way" between A and B.
________________________________________________
  We know that the x-coordinate of this "half-way" point is three.

We can look at the "y-coordinates" of BOTH "Point A" and "Point B".
___________________________
which are "4" and "-2",  respectively.

Now, let us determine the MAGNITUDE of the number of points along the "y-axis" between "y = 4" and y = -2 . 

The answer is:  "6" ;  since, from y = -2 to 0 , there are 2 points, or 2 "units" from y = -2 to y = 0 ;  then, from y = 0 to y = 4, there are 4 points, or 4 "units".

Adding these together,  2 + 4 = 6 units.
______________________________________________
So, the "half-way" point would be 1/2  of  6 units, or 3 units.
__________________________________________________
So, from y = -2 to y = 4 ;  we could count 3 units between these points, along the "y-axis".   Note, we could count "2" units from  "y = -2"  to "y = 0". 
Then we could count one more unit, for a total of 3 units;  from y = 0 to y = 1;  and that would be the answer (y-coordinate of the point).
______________________________________________
Alternately, or to check this answer, we could determine the "halfway" point along the "y-axis" from "y = 4" to "y = -2" ; by counting 3 units along the "y-axis" ; starting starting with "y = 4" ; note:  4 - 3 = 1 ; which is the "y-coordinate" of our answer; that is: "y = 1" ;  and the same y-coordinate we have from the previous (aforementioned) method above.
______________________________________________
We know the "x-coordinate" is "3" ; so the answer:
_________________________________________________
   " (3,1)  is the point that is halfway between <em>A</em> and<em> B </em>." 
__________________________________________________


8 0
3 years ago
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