Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
Answer:
2 7/24C
Step-by-step explanation:
Start by finding the common denominator. In this case, it's 24. Next, start translation.
2/3C = 16/24C
7/8C = 21/24C
3/4C = 18/24C
Then find the sum.
16/24C + 21/24C + 18/24C = 55/24C = 2 7/24C
For this case, what you should keep in mind are the following considerations:
1) Rewrite the expressions correctly using the properties of the exponents: Addition, multiplication, division, subtraction and negative exponents.
2) Simplify the expression as much as possible.
Answer:
See attached image.