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3 years ago

Can anyone help me with this

Mathematics

1 answer:

stiks02 [169]3 years ago

6 0

Answer:

ohh i don't know the answer

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You're flying from Joint Base Lewis-McChord (JBLM) to an undisclosed location 201 km south and 194 km east. Mt. Rainier is locat

elixir [45]

Answer:

The answer is "0.0846276476".

Step-by-step explanation:

Let all the origin(0,0) of JBLM be

Let the y-axis be north along with the vector j unit.

But along the + ve x-axis is east, and all along with the vector unit i.

And at (194,-201) that undisclosed position is

Mt. Ris (56,-40) at

Let the moment it gets close to the Mt. rainier bet.

Oh, then,

If we know, the parallel to the direction from the point was its nearest one to a path to a point,

Calculating slope:

$\to m=\frac{y_2-y_1}{x_2-x_1}\\$

points: (0,0) and (194,-201)

$\to m=\frac{-201 -0 }{194-0}\\\\\to m=\frac{-201}{194}\\\\\to m=-1.03$

equation of the line:

$\to y= mx+c\\\\\to y= -1.03\ x+c$

when the slope is perpendicular= $-\frac{1}{m}$

$= - \frac{1}{ -1.03}\\\\= \frac{1}{ 1.03}\\\\= 0.97$

perpendicular equation:

$\to y-(-40)=0.97 \times (x-56) \\\\\to y+40=0.97 \times (x-56) \\\\$

Going to solve both of the equations to have the intersection point,

We get to the intersect level in order to be at

(47.16,-48.5748)

so the distance from origin:

$= \sqrt{(47.16^2+48.5748^2)}\\\\= \sqrt{2224.0656 + 2359.5112}\\\\=\sqrt{4583.5768}\\\\=67.7021181$

$\to time =\frac{distance }{speed}$

$= \frac{67.7021181}{800}\\\\= 0.0846276476$

6 0

3 years ago

Find 1 2/3 + (-2 1/2)

Elenna [48]

Answer:

you can use a calculator to find this

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the equation linethatis perpendicular to the given line and passes through the point (3,0)?

vladimir1956 [14]

Answer:

3y+x = 3

Step-by-step explanation:

for the point ( 3,0)

x=3 , y= 0

the equation for the line is given as

y-y1= m(x-x1)

for perpendicular ,

m= -1/x

y-0 = -1/3(x-3)

3y= -x +3

3y+x=3

3 0

3 years ago

A rectangle has a perimeter of 32 in. find the length and width of the rectangle under which the area is the largest. follow the

Dafna1 [17]

Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in

5 0

3 years ago

Can someone help me in this please

Karolina [17]

Is the value of b is 5?

5 0

3 years ago

Can anyone help me with this​

Can anyone help me with this