Answer:
it should -1 because you have to evaluate the number
Both the general shape of a polynomial and its end behavior are heavily influenced by the term with the largest exponent. The most complex behavior will be near the origin, as all terms impact this behavior, but as the graph extends farther into positive and/or negative infinity, the behavior is almost totally defined by the first term. When sketching the general shape of a function, the most accurate method (if you cannot use a calculator) is to solve for some representative points (find y at x= 0, 1, 2, 5, 10, 20). If you connect the points with a smooth curve, you can make projections about where the graph is headed at either end.
End behavior is given by:
1. x^4. Terms with even exponents have endpoints at positive y ∞ for positive and negative x infinity.
2. -2x^2. The negative sign simply reflects x^2 over the x-axis, so the end behavior extends to negative y ∞ for positive and negative x ∞. The scalar, 2, does not impact this.
3. -x^5. Terms with odd exponents have endpoints in opposite directions, i.e. positive y ∞ for positive x ∞ and negative y ∞ for negative x ∞. Because of the negative sign, this specific graph is flipped over the x-axis and results in flipped directions for endpoints.
4. -x^2. Again, this would originally have both endpoints at positive y ∞ for positive and negative x ∞, but because of the negative sign, it is flipped to point towards negative y ∞.
Answer:
13 and 32
Step-by-step explanation:
let one number be x
Then the other number is x + 19 , then
x + x + 19 = 45
2x + 19 = 45 ( subtract 19 from both sides )
2x = 26 ( divide both sides by 2 )
x = 13
The 2 numbers are 13 and 13 + 19 = 32
Answer:
a. p1(x) = 2 - x
b. p2(x) = x² - 3*x + 3
c. p1(0.97) = 1.03; p2(0.97) = 1.0309
Step-by-step explanation:
f(x) = 1/x
f'(x) = -1/x²
f''(x) = 2/x³
a = 1
a. The linear approximating polynomial is:
p1(x) = f(a) + f'(a)*(x - a)
p1(x) = 1/1 + -1/1² * (x - 1)
p1(x) = 1 - x + 1
p1(x) = 2 - x
b. The quadratic approximating polynomial is:
p2(x) = p1(x) + 1/2 * f''(a)*(x - a)²
p2(x) = 2 - x + 1/2 * 2/1³ * (x - 1)²
p2(x) = 2 - x + (x - 1)²
p2(x) = 2 - x + x² - 2*x + 1
p2(x) = x² - 3*x + 3
c. approximate 1/0.97 using p1(x)
p1(0.97) = 2 - 0.97 = 1.03
approximate 1/0.97 using p2(x)
p2(0.97) = 0.97² - 3*0.97 + 3 = 1.0309
Answer:
C ( 7, -3 )
Step-by-step explanation:
Question:
which point is 8 units away from ( 7, 5 ) ?
Choices:
A : (0,-3 )B (15,13) C ( 7, -3 ) D ( 1, 5 )
Solution:
(7, 5) and (7, 3) have the same x-coordinate, 7.
They are both on a vertical line that passes through point (7, 0).
(7, 5) is 5 units above the x-axis.
(7, -3) is 3 units below the x-axis.
5 + 3 = 8
(7, 5) and (7, 3) are 8 units apart.
Answer: C ( 7, -3 )
