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RUDIKE [14]
3 years ago
7

Find the shortest distance from A to B in the diagram below.

Mathematics
2 answers:
Ymorist [56]3 years ago
4 0

Answer:

10 cm.

Step-by-step explanation:

We have been given a cuboid. We are asked to find the shortest distance from A to B is the given diagram.

We know that shortest distance from A to B will be equal to hypotenuse of right triangle with two legs 8 meters and 6 meters.

AB^2=8^2+6^2

AB^2=64+36

AB^2=100

Now, we will take square root of both sides of our given equation as:

AB=\sqrt{100}

AB=10

Therefore, the shortest distance from A to B is 10 cm.

klemol [59]3 years ago
3 0

Answer: 14 m

Step-by-step explanation:

8 m + 6 m = 14 m

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Step-by-step explanation:

Given:

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Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
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keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

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