Answer:
The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try! A variable doesn't have to be "x", it could be "y", "w" or any letter, name or symbol. See: Variable.
Step-by-step explanation:
It depend on what question an algebric can have as many but depends???
Answer:
Write in slope-intercept form, y
=
m
x
+
b
y=mx+b.
−
Step-by-step explanation:
Answer:
An explicit representation for the nth term of the sequence:

It means, option (B) should be true.
Step-by-step explanation:
Given the geometric sequence

A geometric sequence has a constant ratio, denoted by 'r', and is defined by

Determining the common ratios of all the adjacent terms

As the ratio is the same, so
r = 4
Given that f₁ = -1/2
substituting r = 4, and f₁ = -1/2 in the nth term


Thus, an explicit representation for the nth term of the sequence:

It means, option (B) should be true.