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Vlad1618 [11]
3 years ago
6

He Was Framed!: Jennifer bought a picture frame for a 4" x 6" picture of her boyfriend. The outside of the frame measures 5" x 7

". If the picture fits inside perfectly, how wide is the frame?

Mathematics
1 answer:
Alex Ar [27]3 years ago
6 0

Answer:

The picture frame is 0.50 inches wide.

Step-by-step explanation:

Consider the image below.

The inner rectangle represents the image of Jennifer's boyfriend.

And the outer rectangle represents the outside of the picture frame.

The width of the picture frame can be computed by subtracting the measures of the respective sides of the two rectangles.

Compute the width using the breadths of the two rectangles as follows:

Width = (Outer Breadth - Inner Breadth) ÷ 2

          = (5 inches - 4 inches) ÷ 2

          = 1 inch ÷ 2

          = 0.50 inches.

Compute the width using the length of the two rectangles as follows:

Width = (Outer Length - Inner Length) ÷ 2

          = (7 inches - 6 inches) ÷ 2

          = 1 inch ÷ 2

          = 0.50 inches.

Thus, the picture frame is 0.50 inches wide.

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erica [24]

Answer: 67.725feet²

Step-by-step explanation:

A heptagon consist of 7 sides and Its area is calculated using the formula

= 1/2 × nsr

n = number of sides = 7

s = side length = 4.3

r = apothem = 4.5

Area = 1/2 × nsr

= 1/2 × 7 × 4.3 × 4.5

= 0.5 × 7 × 4.3 × 4.5

= 67.725feet²

7 0
2 years ago
Sara made 8 necklaces. She used 9 beads on each necklace. The beads came in bags of 6 each. How many bags
motikmotik

Answer:

12 bags

Step-by-step explanation:

9×8=72 beads all together

72/6=12 bags of beads

4 0
2 years ago
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trapecia [35]
Ind. number of people Dep. Cost, rate of change for adult 13$
7 0
3 years ago
it is 3,452 miles round trip to craig's aunt's house.if he travels to her house 3 times this year, how many miles did he travel
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(3,452 * 2) = round trip = 6,904.

6,904 * 3 = total distance = 20,712.

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8 0
3 years ago
A(x, 1), B(5,3) and C(4,-3) are the vertices of triangle ABC. If AB=AC, find the value of x​
Molodets [167]

\\ \rm\longmapsto AB=AC

\\ \rm\longmapsto \sqrt{(x-5)^2+(1-5)^2}=\sqrt{(x-4)^2+(1+3)^2}

\\ \rm\longmapsto (x-5)^2+(-2)^2=(x-4)^2+4^2

\\ \rm\longmapsto (x-5)^2+4=(x-4)^2+16

\\ \rm\longmapsto (x-5)^2-(x-4)^2=16-4=12

\\ \rm\longmapsto x^2-10x+25-x^2+8x-16=12

\\ \rm\longmapsto -2x+9=12

\\ \rm\longmapsto -2x=12-9=3

\\ \rm\longmapsto x=\dfrac{3}{-2}=-1.5

5 0
3 years ago
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