<h3>What is the value of the sum 1/3 + 2/3+ 2/3+ 4/3 + 5/3+6/3+7/3+8/3</h3>
<h2>ANSWER</h2>
![\frac{35}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B35%7D%7B3%7D%20)
Decimal Form:
![11.6](https://tex.z-dn.net/?f=11.6)
Mixed nunber Form:
![11 \frac{2}{3}](https://tex.z-dn.net/?f=11%20%5Cfrac%7B2%7D%7B3%7D%20)
Answer:
D
Step-by-step explanation:
Answer:
Conclusion:
Step-by-step explanation:
Given
We know that the diagonals of a parallelogram bisect each other.
Therefore,
Given RT = x and TP = 5x-28, so
x = 5x-28
5x = x+28
5x-x = 28
4x = 28
divide boh sides by 4
4x/4 = 28/4
x = 7
Thus, the value of x = 7
Similarly,
QT = TS
Given QT = 5y and TS = 2y+12, so
5y = 2y+12
5y-2y = 12
3y = 12
divide both sides by 3
3y/3 = 12/3
y = 4
Thus, the value of y = 4
Conclusion:
Answer:
umm can u explain more plz
Step-by-step explanation: