30 POINTS PLUS BRAINLIEST PLEASE ANSWER THESE MATH QUESTIONS.ALL TROLL ANSWERS WILL BE REPORTED MUST HE DONE IN 1HR OR.LESS.

Mathematics

2 answers:

ipn [44]2 years ago

8 0

Answer:

4) wall = 114 ft^2

$118.56 to paint

5) 77 cm^2

Step-by-step explanation:

4) (15 x 8)-(2 x 3)=120-6=114 ft^2

114 x $1.04 = $118.56

5) (14 x 3.5) + (8 x 3.5) = 49 + 28 = 77 cm^2

svet-max [94.6K]2 years ago

5 0

Answer:

114,$118.56

5. 77

Step-by-step explanation:

To find the area of the wall, you multiply 15 x 8, then subtract (2 x 3) from that answer.

15 x 8 = 120

120 - (3 x 2) =

120 - 6 = 114ft^2

To find the cost, multiply the area by the cost:

1.04 x 114 = $118.56

Since the side with 3.5 cm is congruent with another side, that means that side is also 3.5 cm. I like to break up the figure in this situation, into 2 rectangles. The first is 8 cm x 3.5 cm, and the other being 3.5 cm x 14 cm.

8 x 3.5 = 28 cm^2

14 x 3.5 = 49cm^2

Add together to get the area:

49 + 28 = 77 cm^2

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Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A

iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

$\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA$