Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer:
Section A = 25,000 seats
Section B = 14,600 seats
Section C = 10,400 seats
Step-by-step explanation:
Total Seats = 50,000
Seats in Section A cost = $30
Seats in Section B cost = $24
Seats in Section C cost = $18
Total sales from the event = $1,287,600
No. of Seats in section A = No. seats in Section B + No. seats in Section C
A = B + C
or, 2A = 50,000
A = 25,000 seats @ $30/seat = $750,000
B + C = 25,000
24B + 18C = 537,600
24B + 18(25,000 - B) = 537,600
24B + 450,000 - 18B = 537,600
6B = 87600
B = 14,600
C = 10,400
Hence;
A = 25,000 seats
B = 14,600 seats
C = 10,400 seats
We want to find
, for
.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:
.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)
.
Since 88 has no decimal, you would but a zero behind it and then subtract. You have to borrow from the 8 (make it a 7) and make zero 10. Then subtract. 10-7=3, 7-3=4, 8-4=4. Your answer will be 44.3
Answer:
The y-intercept is 2.5
The x-intercept is 3.5
Step-by-step explanation:
Hope this helps!
