Answer:
B
Step-by-step explanation:
Plug the values of x into each equation
Answer:
67ft
Step-by-step explanation:
2 s =5 an theres
Answer:
c = 4.79 feet
Step-by-step explanation:
Given question is incomplete without a picture; find the question with the attachment.
Two poles AD and DB of same length are leaning against each other.
Distance between the poles (AB) = 45 feet
m(∠ADB) = 180°- (60 + 50)°
= 70°
By sine rule,


= 36.68 ft
Similarly,
DB = 
= 41.47 ft
Now c = DB - AD
= 41.47 - 36.68
= 4.79 feet
The equation will be of the form:

where A is the amount after t hours, and r is the decay constant.
To find the value of r, we plug the given values into the equation, giving:

Rearranging and taking natural logs of both sides, we get:


The required model is:
Answer:

Step-by-step explanation:
Given


Required
Determine Y'
Y' can be solved by multiplying the scale factor by Y
i.e.

For, the x coordinates.

Where




For the y coordinates:

Where




Hence:
