Answer:
Step-by-step explanation:
Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
7*8-4(6-2)+18
56-4(4)+18
56-16+18
40+18
58
6^2-(8*3)+2^2(7*3)
36-24+4(21)
12+84
96
We can set up a system of equations to solve this.
120b + 90d = 270
60b + 110d = 265
To cancel out b, first make the b terms equal.
60b · 2 + 110d · 2 = 265 · 2
120b + 220d = 530
Now subtract the equations.
120b + 90d = 270
-120b + 220d = 530
---------------------------
-130d = -260
Solve for d.
-130d/-130 = -260/-130
d = 2
Now put the value of d in one of the equations.
60b + 110d = 265
60b + 110 · 2 = 265
60b + 220 = 265
60b + 220 - 220 = 265 - 220
60b = 45
60b/60 = 45/60
b = 0.75
Each candy bar sells for $0.75
Hope this helps! :)
