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Orlov [11]
4 years ago
10

Find the area of AABC. Where: A = (-3,3), B=(-4,1), C = (-6,0). W Area:

Mathematics
1 answer:
Luden [163]4 years ago
3 0

Answer: 1.5\text{ square units}

Step-by-step explanation:

We know that the area of triangle with coordinates (x_1,y_1),(x_2,y_2) and (x_3,y_3) is given by :-

\text{Area}=\dfrac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|

Given : The coordinates of ΔABC are  A = (-3,3), B=(-4,1), C = (-6,0).

Then, the area of ΔABC will be :-

\text{Area}=\dfrac{1}{2}|-3(1-0)+(-4)(0-3)+(-6)(3-1)|\\\\\Rightarrow\text{Area}=\dfrac{1}{2}|-3-4(-3)-6(2)|\\\\\Rightarrow\text{Area}=\dfrac{1}{2}|-3+12-12|\\\\\Rightarrow\text{Area}=\dfrac{1}{2}|-3|=\dfrac{1}{2}(3)=1.5

Hence, the area of ΔABC= 1.5\text{ square units}

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Answer:

i would say

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Step-by-step explanation:

2x + 4y = 123 + 31

2x +4y = 154

4y = 154 -2x

y = ( 154 - 2x ) / 4

y = ( 77 - x ) / 2

6 0
3 years ago
One-step equations with rational coefficients solve each equation. 1) 34a = 14 2) -29=-32m
FrozenT [24]
1)
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2)
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</span>
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3 years ago
Assuming only the lengths of the sides of a triangle are given, how can you determine if the triangle has a right angle?
saveliy_v [14]

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Which statement is true? Question 12 options: A) |–3| = 3 and –|–4| = –4 B) |–3| = 3 and |–4| = –4 C) |–3| = 3 and –|4| = 4 D) –
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Need help with thisss
frozen [14]

9514 1404 393

Answer:

  cos(x) = 0.6

Step-by-step explanation:

First, we need to find UQ.

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Then TQ is ...

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