How do i solve a triangles area
1 answer:
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Answer:
After 2 seconds
Step-by-step explanation:
First step is find an equation of velocity:
h(t)=-16t2+64t+112. The velocity function is derivated from position function, so we should do that.
v(t)= h´(t)= -16*2*t+64 ⇒ v(t)= -32t+64.
Now we know the arrow reach the maximun height when this velocity is equal to zero when t>0.
0=-32t+64 ⇒ 32t=64, split each member for 32 ⇒ =
t=2. That means after 2 sec. the arrow reach the maximum height
Answer:
Part A:
( 1.8333, -0.08333)
Part B:
x = 2 or x = 5/3
Step-by-step explanation:
The quadratic equation
has been given.
Part A:
We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.
Setting the derivative to 0;
6x - 11 = 0
6x = 11
x = 11/6
The corresponding y value is determined by substituting x = 11/6 into the original equation;
y = 3(11/6)^2 - 11(11/6) + 10
y = -0.08333
The vertex is thus located at the point;
( 1.8333, -0.08333)
Find the attached
Part B:
We can use the quadratic formula to solve for x as follows;
The quadratic formula is given as,
From the quadratic equation given;
a = 3, b = -11, c = 10
We substitute these values into the above formula and simplify to determine the value of x;
