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MariettaO [177]
3 years ago
9

Write an equation for the graphed line in......please help.

Mathematics
1 answer:
liq [111]3 years ago
4 0

The graphed line is y = 3/2x + 3.

In order to solve for this, we need to start by finding the slope. To find the slope, we start by selecting two points on the graph. We'll use (0, 3) and (-2, 0).

m(slope) = (y2 - y1)/(x2 - x1)

m = (3 - 0)/(0 - -2)

m = 3/2

Now that we have this, we can use a point and slope intercept form to find the intercept.

y = mx + b

0 = (3/2)(-2) + b

0 = -3 + b

3 = b

And we can use the slope and intercept to model the equation as y = 3/2x + 3

You might be interested in
Let x △ y be defined by x △ y=x−5y. What is the value of 3 △  (−4)
TEA [102]

x\Delta y=x-5y\\\\3\Delta(-4)\qquad\text{put the values x = 3 and y = -4 to the expression x - 5y}:\\\\3\Delta(-4)=3-5(-4)=3+20=23

5 0
4 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
Addison earn $25 mowing her neighbor's lawn then she loaned her friend $18 and got 50 from her grandmother for her birthday she
yarga [219]

Solution: The total money did addison have to begin with is $29.

Explanation:

Let the addison begin with money $x.

It is given that the addison earn $25 from his neighbor and $50 from her grandmother. So total money addison has \$x+\$25+\$50=\$x+\$75

She loaned her friend %18.

Now she has \$x+\$75-\$18=\$x+\$57

It is given that she had $86.

\$x+\$57=\$86\\\$x=\$86-\$57\\\$x=\$29

Therefore, the total money did addison have to begin with is $29.

4 0
4 years ago
Read 2 more answers
C
egoroff_w [7]

Answer:

Step-by-step explanation:

Answer:

$125  

Explanation:

Cost of meal                           =  $100

+ 5 % sales tax = 0.05 × 100 = +      5

+ 20 % tip         = 0.20 × 100 =  <u>     20</u>

Total cost                               =   $125

The total cost of the meal was $125.

8 0
3 years ago
What is the slope-intercept equation for the line below? (0,1) (4,3)
levacccp [35]

y2 - y1

---------

x2 - x1

3 - 1        2            1

------- = -------- = --------

4 - 0        4            2

Find the y-intercept:

1 = 1/2(0) + b

1 = 0 + b

-0  -0

1 = b

The slope-intercept equation is:

y = 1/2x + 1

so its D


6 0
3 years ago
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