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Lemur [1.5K]
3 years ago
6

I need help with thishistogram

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
4 0
A is what I thinkkkk
You might be interested in
Which ordered pair is a solution of this equation? -9x-5y=12
Sidana [21]
-9x-5y=12
C) (2, -6)  -18+30=12
7 0
3 years ago
I’m confused :( I will mark as Brainliest and give you points
Ludmilka [50]

Answer:

123.5 square inches

Step-by-step explanation:

Given: To find the area of a rectangle, you have to multiply base times height.

To find the area of a triangle, you have to do base times height devided by 2.

Finding the area: Let's break up this shape into polygons. At the bottom there is a rectangle. We know that to find the area of the rectangle you have to do base times height. 13in•7in will give you <u>91in</u> square for the rectangle.

Now for the triangle. If you can see, if you break the triangle in half, there are 2 right triangles. Let's look at the right one for now. Since we know that to find the area of a triangle you have to do base times height divided by 2,  you do 5in•6.5in=32.5in. 32.5in divided by 2 is <u>16.25in </u>square which is the area of one triangle. You might be wondering why i did 5•6.5, and that's because at the bottom of the rectangle you can see it's 13in, and 13in÷2=6.5in.

We already found the area of the rectangle and one triangle. The other triangle is equal to it so we can just do 16.25+16.25=<u>32.5in</u> square for both of the triangles.

Now we add it all up: 32.5+91=123.5 square inches

8 0
3 years ago
I need help fast... if answered Correctly I will mark brainliest
Lesechka [4]

9514 1404 393

Answer:

  (-5,1)

Step-by-step explanation:

To eliminate x, multiply the first equation by 3 and add 2 times the second equation.

  3(-2x +7y) +2(3x -4y) = 3(17) +2(-19)

  -6x +21y +6x -8y = 51 -38

  13y = 13

  y = 1 . . . . . matches the third answer choice

  (x, y) = (-5, 1)

5 0
3 years ago
The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term
Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be 1, 5, and 25.

The sum of the first seven terms of the geometric sequence would be 127.

Step-by-step explanation:

<h3>1.</h3>

Let d denote the common difference of the arithmetic sequence.

Let a_1 denote the first term of the arithmetic sequence. The expression for the nth term of this sequence (where n\! is a positive whole number) would be (a_1 + (n - 1)\, d).

The question states that the first term of this arithmetic sequence is a_1 = 1. Hence:

  • The third term of this arithmetic sequence would be a_1 + (3 - 1)\, d = 1 + 2\, d.
  • The thirteenth term of would be a_1 + (13 - 1)\, d = 1 + 12\, d.

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let r denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d.

Ratio between the third term and the second term of the geometric sequence:

\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}.

Both (1 + 2\, d) and \left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right) are expressions for r, the common ratio of this geometric sequence. Hence, equate these two expressions and solve for d, the common difference of this arithmetic sequence.

\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}.

(1 + 2\, d)^{2} = 1 + 12\, d.

d = 2.

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be 1, (1 + (3 - 1) \times 2) = 5, and (1 + (13 - 1) \times 2) = 25, respectively.

These three terms (1, 5, and 25, respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be r = 25 /5 = 5.

<h3>2.</h3>

Let a_1 and r denote the first term and the common ratio of a geometric sequence. The sum of the first n terms would be:

\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}.

For the geometric sequence in this question, a_1 = 1 and r = 25 / 5 = 5.

Hence, the sum of the first n = 7 terms of this geometric sequence would be:

\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}.

7 0
2 years ago
(01.05 MC)The total charge on 6 particles is −48 units. All the particles have the same charge. What is the charge on each parti
Elina [12.6K]

Answer: -9 units

Step-by-step explanation:

-9 x 4 = -36

so therefore -36 divided by 4 = -9

5 0
3 years ago
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