(6 mph)x + (10 mph)x = 48 mi. Then (16 mph)x = 48 mi, and x = 3 hrs (answer)
Answer:
1: 14/17
2:
Step-by-step explanation:
1:
4 2/3 ÷ 5 6/9 =
14/3 ÷ 51/9 =
14/3 • 9/51 =
14/1 • 3/51 =
42/51 =
14/17
2:
5 4/9 • 6 7/9 =
49/9 • 61/9 =
fraction: 2989/81 or mixed number: 36 73/81
Hopefully that is what you wanted!
Answer:
You buy six newspaper ads & eighteen social media ads.
Step-by-step explanation:
First, we change ads into variables to be more easier to calculate :
Let newspaper = x
Let social media = y
Second, make this variables into an equation, given that you purchase a total of 24 ads :
x + y = 24 (first equation)
Next, given that x = $18.50 & y = $26.50 & spent a total of $588 so you can make another equation :
18.50x + 26.50y = 588 (second equation)
Now, solve this simultaneous equation using elimination or substitution (depends on you) :
substitution =>
x + y = 24 ----------(1)
18.50x + 26.50y = 588 ---------(2)
(1)=> y = 24 - x ------(3)
(3)=>(2) 18.5x + 26.5(24-x) = 588
18.5x + 636 - 26.5x = 588
-8x = -48
x = 6
sub x=6 into(3)
(3)=> y = 24 - 6
= 18
newspaper = x
= 6
social media = y
= 18
Answer:
A. Miguel has the greatest spread.
The range of the two persons can be determined by:
Adam's range = 106 -91
= 15
Miguel's range = 105 -86
= 19
B. Considering the middle 50% of the training time, the person with the least spread is Adam.
Adam - 103 105 104 106 100
Miguel - 88 86 89 93 105
Adam's 50% range = 106 - 100
= 6
Miguel's 50% range = 105 - 86
= 19
Adam has the least spread
C. Miguel is inconsistent with the time set for training compared to that of Adam.
The answers to parts 2a and 2b show that there is a wide variation in the time that Miguel spend during training, but a minimum variation in the time spent by Adam during training.
16. no i dont agree. 1 is the only number that can multiply and equal itself. also, 0.1 is not even a whole number
17. it took 19 to 21 hours. one way to show work is by long division. i dont know how to do another way im so sorry
18. because 15000 is the amount in 50 minutes, so just divide 50 minutes of phones by 50 to get one minute of phones
i am worn out i cant do the last one
