use long division or synthetic division
I will use long
y-3 times y=y^3-3y
subtract that from y^2-y-11
we are left with
2y-11
multiply y-3 by 2 and get 2y-6
subtract that from 2y-11
get 5 as a remainder
answer is y+2+5/(y-3)
= 3 ⋅ 2
= 6 is the rational numbe
Answer:
hi sadly I can't find the proper answer for you, tried working it out
Answer:
infinitely many
Step-by-step explanation:
Combine like terms on the right-hand side:
14t-20=14t-20
Add 20
14t=14t
divide by 14
t=t
this means that there are infinitely many solutions
