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Yuri [45]
3 years ago
13

A bakery offers a sale price of $2.90 for 3 muffins. What is the price per dozen?

Mathematics
2 answers:
Tema [17]3 years ago
5 0

Answer: $11.60 per dozen

Step-by-step explanation:

2.90=3 muffins

Multiply both sides by 4

3x4=12 ( a dozen)

2.90x4= 11.60

Hope this helps :)

KatRina [158]3 years ago
3 0
A dozen is 12, divide by 3 since that’s where the deals at, 12/3 = 4 . multiple 4 times 2.90 and the price is $11.60
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Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

System #2: x=1

x+2y=5\\2x+y=4

Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

<em>all real numbers are solutions</em>

System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

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System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

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2 years ago
If james has 4 apples and thalia has 6 apples how many apples do they have all together
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Answer:

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Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

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Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = \frac{20}{12}

t = \frac{5}{3} days

Therefore, there are two intervals in which the given function is defined

(0, \frac{5}{3}) and (\frac{5}{3}, ∞)

For the interval (0, \frac{5}{3}),

p'(1) = 20 - 12(1) = 20

For the interval (\frac{5}{3}, ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, \frac{5}{3}) indicates that the function is increasing.

0 < t < \frac{5}{3}

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

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Which expression is eq to (125^2/125^4/3)
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Answer:

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Now our new fraction is \frac{125^{2} }{5^{4} } = \frac{15625}{625} which then simplifies to 25

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