The sides length of the cubical box is 3.8 cm if the volume of a cubical box is 54.872 cm³ option second is correct.
<h3>What is a cube?</h3>
It is defined as three-dimensional geometry that has six square faces and eight vertices.
We have a volume of a cubical box is 54.872 cm³
V = 54.872 cm³
As we know the volume of the cube:
V = side³
54.872 = side³
Taking cube root on both sides:
side = 3.8 cm
Thus, the sides length of the cubical box is 3.8 cm if the volume of a cubical box is 54.872 cm³ option second is correct.
Learn more about the cube here:
brainly.com/question/15420947
#SPJ1
P=2(L+W)
A=LW
given
P=62
62=2(L+W)
divide 2
31=L+W
minus W
L=31-W
sub into other one
A=LW
A=(31-W)(W)
228=31W-W^2
times -1
W^2-31W=-228
add 228 both sides
W^2-31W+228=0
factor
what 2 numbers multiply to get 228 and add to get -31
-19 and -12
(W-19)(W-12)=0
set to zero
W-19=0
W=19
W-12=0
W=12
sub back
L=31-W
L=31-12
L=19
or
L=31-19
L=12
the doorway is 12in by 19in
Answer:
This is not a right triangle(No)
Step-by-step explanation:
Answer:
x = 3/2 or x = -5/4
Step-by-step explanation:
Solve for x over the real numbers:
8 x^2 - 2 x - 15 = 0
Using the quadratic formula, solve for x.
x = (2 ± sqrt((-2)^2 - 4×8 (-15)))/(2×8) = (2 ± sqrt(4 + 480))/16 = (2 ± sqrt(484))/16:
x = (2 + sqrt(484))/16 or x = (2 - sqrt(484))/16
Simplify radicals.
sqrt(484) = sqrt(4×121) = sqrt(2^2×11^2) = 2×11 = 22:
x = (2 + 22)/16 or x = (2 - 22)/16
Evaluate (2 + 22)/16.
(2 + 22)/16 = 24/16 = 3/2:
x = 3/2 or x = (2 - 22)/16
Evaluate (2 - 22)/16.
(2 - 22)/16 = -20/16 = -5/4:
Answer: x = 3/2 or x = -5/4
Answer:
8. -3, 16
9. -3, 4.5
Step-by-step explanation:
See attached worksheet.
