Help!In the figure below, triangle ABC is an equilateral triangle, and quadrilateral DEFB is a square.
1 answer:
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Question #1
Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5. So the y-intercept is 5.
Part B:
The slope is 22.
Part C:
y = mx + b
y = 22x + 5
We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10
The domain is 10.
Question #2
Part A:
(2,255)
(5,480)
Standard form is Ax + By = C
Let's plug this into this form first:
Now, let's make it into Standard Form.
What, which is in the box, is your final answer. :)
Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)
Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5. So the y-intercept is 5.
Part B:
The slope is 22.
Part C:
y = mx + b
y = 22x + 5
We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10
The domain is 10.
Question #2
Part A:
(2,255)
(5,480)
Standard form is Ax + By = C
Let's plug this into this form first:
Now, let's make it into Standard Form.
What, which is in the box, is your final answer. :)
Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)