Answer:
<em>100feet</em>
Step-by-step explanation:
Given the height of the object modelled by the equation
y = -16x^2 + 48x + 64
We can find the maximum height reached by the object since we are not told what to find.
The velocity of the object at its max height is zero.
dy/x = 0
dy/dx = -32x + 48
0 = -32x + 48
32x = 48
x = 48/32
x = 1.5secs
get the max height by substituting x = 1.5 into the given equation:
y = -16x^2 + 48x + 64
y = -16(1.5)^2 + 48(1.5)+ 64
y = -36+72+64
<em>y = 100 feet</em>
<em>Hence the maximum height reached by the object is 100feet</em>
A = 1/2h(b1+b2)
A = 1/2(8)(19+11)
A = 4(30)
A= 120m^2
Hope this helps! :)
The answer is d. Hope this helps:)
