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Brrunno [24]
3 years ago
10

A poster is 16 inches wide by 20inches long. You use a copier to create a reduction whith a scale factor of of 3/4 .will the red

uction fit into a frame taht is 11 inches by 17 inches ?
Mathematics
1 answer:
velikii [3]3 years ago
7 0
No. If u divide the 16*20 inch poster by 4 u will get a poster 12*15 so it will not fit in a frame 11 by 17
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A particle moves with velocity vector
asambeis [7]

Answer:

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-(2t+1)\hat{j}+(\frac{1}{3}t^3+1)\hat{k}

Step-by-step explanation:

We are given that velocity vector of a particle

\vec{v(t)}=t\hat{i}-2\hat{j}+t^2\hat{k}

When t=0 then the particle is at the point (0,-1,1).

We have to find the position of particle  at time t.

We know that

Velocity =\frac{Displacement }{time}=\frac{ds}{dt}

Therefore,\vec{v}=\frac{\vec{ds}}{dt}

\int{ds}=\int (t\hat{i}-2\hat{j}+t^2\hat{k})dt

Integrate on both sides then we get

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-2t\hat{j}+\frac{1}{3}t^3\hat{k}+C

\int x^n dx=\frac{x^{n+1}}{n+1}+C

Substitute the value of point at time t=0 then we get

C=-\hat{j}+\hat{k}

Substitute the value of C then we get

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-2t\hat{j}+\frac{1}{3}t^3\hat{k}-\hat{j}+\hat{k}

Therefore, the position of particle at time t

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-(2t+1)\hat{j}+(\frac{1}{3}t^3+1)\hat{k}

8 0
3 years ago
-2x+1=7 how do I do this?
ivanzaharov [21]

Answer: x=-3


Step-by-step explanation: -2x+1=7

-2x=7-1

-2x=6

-2x/-2=6/-2

X=-3


5 0
3 years ago
Read 2 more answers
Work out the value of x
weqwewe [10]

Answer:

20

Step-by-step explanation:

4x+5x=180

x=20

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3 years ago
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Here is a picture of a cube, and the net of this cube.
dimaraw [331]
Formula: 6x^2
Answer:726
6 0
3 years ago
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Given that the points (16,-5)and (-40,16) lie on a line what is the slope of the line
irakobra [83]

Answer:

-3/8 I think

Step-by-step explanation:

16 - ( - 5)  = 21 \div   ( - 40) - 16 =  - 56

then u just simplify it which is -3/8

7 0
3 years ago
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