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8090 [49]
3 years ago
7

Solve for x,y, and z

Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0
Equation 1)  3x + 2y - 5z = 3
Equation 2)  4x - 2y - 3z = -10
Equation 3)  5x - 2y - 2z = -11

Add equation 1 with equation 2.

Equation 4)  7x - 8z = 7

Then subtract equation 3 from equation 2.

Equation 5)  -x -z = 1

Multiply all of equation 5 with 7.

5)  -7x - 7z = 7
4)  7x - 8z = 7

Add equations together.

z = 14

Plug in 14 for z in equation 4.

7x - 8z = 7

7x - 8(14) = 7

7x - 112 = 7

7x = 119

x = 17

Plug in 17 for x in equation 1, and 14 for z.

1)  3x + 2y - 5z = 3

3(17) + 2y - 5(14) = 3

51 + 2y - 70 = 3

2y - 19 = 3

2y = 22

y = 11

So, x = 17, y = 11, and z = 14

~Hope I helped!~



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4 0
2 years ago
Read 2 more answers
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

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Answer:

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