Answer: 120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]
Step-by-step explanation:
=24x(x^2 + 1)4(x^3 + 1)5 + 42x^2(x^2 + 1)5(x^3 + 1)4
Remove the brackets first
=[(24x^3 +24x)(4x^3 + 4)]5 + [(42x^4 +42x^2)(5x^3 + 5)4]
=[(96x^6 + 96x^3 +96x^4 + 96x)5] + [(210x^7 + 210x^4 + 210x^5 + 210x^2)4]
=(480x^6 + 480x^3 + 480x^4 + 480x) + (840x^7 + 840x^4 + 840x^5 + 840x^2)
Then the common:
=[480(x^6 + x^3 + x^4 + x) + 840(x^7 + x^4 + x^5 + x^2)]
=120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]
Answer:
u=5.23
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
y^1 = 5^1 (y = 5)
Anything raised to the power of 1 is just itself.
So, 5^1 = 5
The answer would be they are congruent.
It's because there was no vertical/horizontal stretch and compression listed in the problem's transformations. The figure was translated throughout the graph.
Answer:
A Bar Graph
Step-by-step explanation:
This would be the best choice make the x axis the sports
and the y axis the numbers and make 2 bars for each sport one for girls one for boys
