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pickupchik [31]

3 years ago

11

it takes Pam 45 minutes to drive to work and 60 minutes to drive home from work.write the ratio of he time Pam spends driving ho

me from work to the time she spends driving to work in tree different ways.

1 answer:

Sauron [17]3 years ago

4 0

12:9, 12/9, and 12 to 9. The way I got 12 and 9 was by simplifying 60/45.

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Write 10 x 10 x 10 x 10 x 10 x 10 with an exponent. Explain how you decided what exponent to write

valentina_108 [34]

10x10x10x10x10x10=1000000

${10}^{6}$

means 10x10x10x10x10x10

as it's basically saying 10 is multiplied by itself 6 times which gives you 1000000

5 0

3 years ago

Read 2 more answers

What is the slope of the line?<br> A. 3/4<br> B. -3/4<br> C. -4/3<br> D. 4/3

pashok25 [27]

(0,0) (3,4)
(4-0)/(3-0) = 4/3
The slope is 4/3

4 0

3 years ago

Read 2 more answers

A traveler is walking on a moving walkway in an airport The Traveler must walk back on the walkway to get a bag he forgot the Tr

hichkok12 [17]

Let the speed off the walk way be x and speed of the walkway be y
x+y=6....i
x-y=2....ii
adding the above equation we get:
2x=8
thus
x=4 ft/s
and
y=6-4=2 ft/s
thus the speed off the walk way is 4 ft/s
the speed of the moving walkway is 2 ft/s

6 0

3 years ago

What is [3.4(6x+2)+3]+4p-3x? PLS need help

inna [77]

Step 1: simplify

[3.4 ( 6 x + 2 ) +3] + 4 p -3 x

Pemdas!

6x+2=8x

3.4+3=6.4

6.4+8x=14.4

14.4x+4p=18.4xp+3= 21.4xpx

x=8

p=18.4

Other x = 21.4

3 0

3 years ago

Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

$L_\lambda=x^2+y^2-9=0$

Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.

4 0

3 years ago