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3 years ago

8

If using the method of completing the square to solve the quadratic equation x^2-19x+9=0x

1 answer:

riadik2000 [5.3K]3 years ago

7 0

19/2 = 9.5
(9.5)^2 = 90.25 = 9 + 81.25

x^2 - 19x + 9 = 0
x^2 - 19x + 90.25 - 81.25 = 0
(x - 9.5)^2 = 81.25
x - 9.5 = +/-sr(81.25)

I will let you finish from here

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Lf 7 + 3x = 22. then 2x = ?

Sloan [31]

Answer:

2x = 10

Step-by-step explanation:

7 + 3x = 22

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3x = 15

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Divide both sides by three to get the variable alone.

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3 years ago

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3 years ago

I rlly need help with this :(

kobusy [5.1K]

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 72.6, \sigma = 2.7$ .

Item a:

The percentile is the <u>p-value of Z when X = 74.2</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{74.2 - 72.6}{2.7}$

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the <u>p-value of Z when X = 78 subtracted by the p-value of Z when X = 70</u>, hence:

X = 78:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{78 - 72.6}{2.7}$

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{70 - 72.6}{2.7}$

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

More can be learned about the normal distribution at brainly.com/question/4079902

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