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Anon25 [30]
3 years ago
12

How can you increase the momentum of an object

Physics
2 answers:
77julia77 [94]3 years ago
6 0
The answer is <span>B. by increasing its mass. Hope it help!</span>
ICE Princess25 [194]3 years ago
4 0
<span>Increase the object's speed, or its mass or both </span>
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What is the amount of charge a capacitor can store per volt of potential difference?
sladkih [1.3K]

The amount of charge a capacitor can store per volt of potential difference is called the capacitance of the capacitor.

<h3>What is the capacitance?</h3>

The capacitance has to do with the amount of charge that is stored by a capacitor. We know that a capacitor is a device that can be used to store electric charges. We have in it, two capacitors separated by a dielectric material.

Hence, the amount of charge a capacitor can store per volt of potential difference is called the capacitance of the capacitor.

Learn more about capacitor:brainly.com/question/17176550

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4 0
2 years ago
Read 2 more answers
Electrons of wavelength 1.5 nm are emitted from a material when light of wavelength 350nm is incident on it. What is the work fu
krok68 [10]

Answer:

3.5434 eV

Explanation:

For a particle with kinetic energy E and mass m , the wavelength  associated is given by the following relation,

\lambda=\frac{h}{\sqrt{2mE} }

E = \frac{h^2}{2m\lambda^2}

Putting the values  we get

E = \frac{(6.6\times(10^{-34})^2}{2\times9.1\times10^{-31\times(1.5\times10^{-9})^2}}

=1.063 x 10⁻²¹ J

= .0066 eV.

Energy of¹light in terms of eV

= 1244 / 350 = 3.55 eV.

Work function = 3.55 - 0.0066 = 3.5434 eV.

7 0
4 years ago
How are scientific methods used to answer a question???
Oksanka [162]
You fallow the steps to figure out the complete answer of the question.
7 0
3 years ago
A ball of mass m and weight mg is held at rest by two strings. One string makes an angle θ with the vertical. The other is horiz
malfutka [58]

Answer:

W = M g          weight of ball

T cos θ  = W         balancing vertical forces

T sin θ = F            balancing horizontal forces

tan θ = F / W        dividing equations

F = W tan θ          when θ equals zero F equals zero

6 0
2 years ago
A horizontal circular platform (m = 119.1 kg, r = 3.23m) rotates about a frictionless vertical axle. A student (m = 54.3kg) walk
Murrr4er [49]

Answer:

\omega_2=5.1rad/s

Explanation:

Since there is no friction angular momentum is conserved. The formula for angular momentum thet will be useful in this case is L=I\omega. If we call 1 the situation when the student is at the rim and 2 the situation when the student is at r_2=1.39m from the center, then we have:

L_1=L_2

Or:

I_1\omega_1=I_2\omega_2

And we want to calculate:

\omega_2=\frac{I_1\omega_1}{I_2}

The total moment of inertia will be the sum of the moment of intertia of the disk of mass m_D=119.1 kg and radius r_D=3.23m, which is I_D=\frac{m_Dr_D^2}{2}, and the moment of intertia of the student of mass m_S=54.3kg at position r (which will be r_1=r=3.23m or r_2=1.39m) will be I_{S}=m_Sr_S^2, so we will have:

\omega_2=\frac{(I_D+I_{S1})\omega_1}{(I_D+I_{S2})}

or:

\omega_2=\frac{(\frac{m_Dr_D^2}{2}+m_Sr_{S1}^2)\omega_1}{(\frac{m_Dr_D^2}{2}+m_Sr_{S2}^2)}

which for our values is:

\omega_2=\frac{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(3.23m)^2)(3.1rad/s)}{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(1.39m)^2)}=5.1rad/s

6 0
3 years ago
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