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timofeeve [1]
1 year ago
13

A ball of mass m and weight mg is held at rest by two strings. One string makes an angle θ with the vertical. The other is horiz

ontal. What is the tension in the horizontal string?.
Physics
1 answer:
malfutka [58]1 year ago
6 0

Answer:

W = M g          weight of ball

T cos θ  = W         balancing vertical forces

T sin θ = F            balancing horizontal forces

tan θ = F / W        dividing equations

F = W tan θ          when θ equals zero F equals zero

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A wire lying along a y axis form y=0 to y=0.25 m carries a current of 2.0 mA in the negative direction of the axis. The wire ful
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Answer:

FB = 0.187 N

Explanation:

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the angle between B and L is given by:

\vec{L}\cdot\vec{B}=LBcos\theta\\\\\theta=cos^{-1}(\frac{\vec{L}\cdot\vec{B}}{LB})=cos^{-1}(\frac{0*0.3y+0.25*0.4y}{0.25*0.5y})=36.86\°

Due to B depends on "y" you take into account the contribution of each element dy of the wire to the magnitude of the magnetic force. Thus, you have to integrate the following expression:

|\vec{F_B}|=Isin\theta\int_0^{0.25}B(y)dy=Isin\theta\int_0^{0.25}(0.5y)dy\\\\|\vec{F_B}|=(2.0*10^{-3}A)(sin36.86\°)(0.5T)[\frac{0.25^2}{2}m]=0.187\ N

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