Ask question

Ask question

All categories

2 years ago

13

A ball of mass m and weight mg is held at rest by two strings. One string makes an angle θ with the vertical. The other is horiz

ontal. What is the tension in the horizontal string?.

1 answer:

malfutka [58]2 years ago

6 0

Answer:

W = M g weight of ball

T cos θ = W balancing vertical forces

T sin θ = F balancing horizontal forces

tan θ = F / W dividing equations

F = W tan θ when θ equals zero F equals zero

You might be interested in

What is a disadvantage of using moving water to produce electricity

klemol [59]

Most of the time the towns get flooded and many people die and lose their homes and their jobs, businesses by the floods and the natural environment is destroyed ,air pollution is produced, the ecosystem could be disrupted and dams are known to fall over and dams are really expensive to build, The dams also cause geological damage, example earthquakes and spills happen.

4 0

3 years ago

If Ike notices that there is a new moon tonight, when should he expect there to be a new moon again?

podryga [215]

Whatever phase of the moon Ike sees, he can expect to see
the same phase of moon again, after 29.53 days later.

5 0

3 years ago

PLS Can someone help me with this I don’t know how to do it. I’ll give brainliest to whoever answers it.

Stolb23 [73]

Answer:

I think this is how you do it

Explanation:

4 0

3 years ago

Gemiola [76]

The Mass of the barter and the ball is 3.1kg

Data Given;

F = 1.1*10^-9N
r = 0.76m
G = 6.67*10^-11 m^3 kg^-1 s^-1

Assuming the barter and the ball have equal mass, we can apply gravitational force formula.

<h3>Gravitational Force</h3>

$F = \frac{Gm_1m_2}{r^2}$

This is product of the mass of the two bodies and divided by the square of their distance apart.

Substituting the values into the formula

$F = \frac{Gm_1m_2}{r^2\\}\\m_1 = m_2 = m\\1.1*10^-^9=\frac{6.67*10^-^1^1*m^2}{0.76^2} \\m^2 = \frac{1.1*10^-^9*0.76^2}{6.67*10^-^1^1} \\m^2 = 9.525\\m = \sqrt{9.525}\\m =3.086=3.1kg$

From the calculations above, the mass of the barter and the ball is 3.1kg

Learn more on gravitational force here;

brainly.com/question/11359658

8 0

3 years ago

The Cosmoclock 21 Ferris wheel in Yokohama City, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which

Slav-nsk [51]

Answer:

V = 5.24m/s

Explanation:

See attachment below.

5 0

4 years ago