Answer:
5.49×10⁻⁴ lbm
Explanation:
Convert volume to m³.
V = (200 cm³) (1 m / 100 cm)³ = 0.0002 m³
Find mass in kg.
m = ρV
m = (1.24507 kg/m³) (0.0002 m³)
m = 0.000249 kg
Convert mass to lbm.
m = (0.000249 kg) (2.205 lbm/kg)
m = 0.000549 lbm
m = 5.49×10⁻⁴ lbm
Answer:
The speed of the ball is 9.07 m/s.
Explanation:
Given that,
Mass of the lead ball, m = 55 kg
Height of the tower, h = 55 m
We need to find the speed of the ball it has traveled 4.20 m downward, x = 4.2 meters
The initial speed of the ball will be 0 as it was at rest initially. Let v is the speed of the ball after it has traveled 4.20 m downward. It is a case of equation of motion such that :
Here, a = g
v = 9.07 m/s
So, the speed of the ball is 9.07 m/s. Therefore, this is the required solution of given condition.
Answer:
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Explanation:
Hope you get it right!
Answer:
The speed should be reduced by 1/√2 or 0.707 times
Explanation:
The relationship between the kinetic energy, mass and velocity can be represented by the following equation:
K.E = ½m.v²
In this equation, the mass is inversely proportional to the square of the velocity or speed. This means that as the mass increases, the speed reduces by × 2.
Let; initial mass = m1
Final mass = m2
Initial velocity = v1
Final velocity = v2
According to the question, if the mass of the body is doubled i.e. m2 = 2m
½m1v1² = ½m2v2²
½ × m × v1² = ½ × 2m × v2²
Multiply both sides by 2
(½ × m × v1²)2 = (½ × 2m × v2²)2
m × v1² = 2m × v2²
Divide both sides by m
v1² = 2v2²
Divide both sides by 2
v1²/2= v2²
Square root both sides
√v1²/2= √v2²
v1/√2 = v2
v2 = 1/√2 v1
This shows that to maintain the same kinetic energy if the mass is doubled, the speed should be reduced by 1/√2 or 0.707 times.
