Answer:
hello your question lacks some data and required diagram
G = 77 GPa, т all = 80 MPa
answer : required diameter = 252.65 * 10-^3 m
Explanation:
Given data :
force ( P ) = 660 -N force
displacement = 15 mm
G = 77 GPa
т all = 80 MPa
i) Determine the required diameter of shaft BC
considering the vertical displacement ( looking at handle DC from free body diagram )
D' = 0.3 sin∅ , where D = 0.015
hence ∅ = 2.8659°
calculate the torque acting at angle ∅ of CD on the shaft BC
Torque = 660 * 0.3 cos∅
= 660 * 0.3 * cos 2.8659 = 198 * -0.9622 = 190.5156 N
hello attached is the remaining part of the solution
Before the engines fail 
, the rocket's horizontal and vertical position in the air are
and its velocity vector has components
After 
, its position is
and the rocket's velocity vector has horizontal and vertical components
After the engine failure 
, the rocket is in freefall and its position is given by
and its velocity vector's components are
where we take 
.
a. The maximum altitude occurs at the point during which 
:
At this point, the rocket has an altitude of
b. The rocket will eventually fall to the ground at some point after its engines fail. We solve 
for 
, then add 3 seconds to this time:
So the rocket stays in the air for a total of 
.
c. After the engine failure, the rocket traveled for about 34.6 seconds, so we evalute 
for this time :
We have the equation of motion 
, where v i the final velocity, u is the initial velocity, a is the acceleration and s is the displacement
Here final velocity, v = 40m/s
Initial velocity, u = 0 m/s
Displacement s = 2 m
Substituting 
So the baseball pitcher accelerates at 400m/
to release a ball at 40 m/s.
Mass is measured in kg
Velocity is measured in ms^-1
Hope this is what you were looking for
Answer:
Explanation:
compressions and rarefactions
