Question

9. During training, a hurdler wants to raise the height of the hurdles from the high school standard of 39 inches to the

Answer 1

Answer:

Something doesn't make sense. The time when his height is 0 is time t=0 and t=25.

The vertex would be halfway in between at time t=(0+25)/2 = 12.5 seconds.

But plugging that in, we get a height of:

3.90625 inches

I think you must have a typo... let's try this equation instead:

h(t) = (-0.25t)(t - 25)

In that case, the maximum at h(12.5) is 39.0625 inches.

Answer:

No, the function for his height has him just barely clearing 39 inches. He can't clear 42 inches.

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