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aliya0001 [1]
2 years ago
5

What is 12 divided by 1 using long division

Mathematics
2 answers:
sergeinik [125]2 years ago
7 0

Answer:

12

Step-by-step explanation:

12 divided by 1 using long division is 12. As long as a number is divided by 1 the number is the same as the dividends number.

Charra [1.4K]2 years ago
7 0

Answer:

12

Step-by-step explanation:

1 2. 0

1 1 2. 0

− 1    

 0 2  

−   2  

   0 0

 −   0

     0

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There are many cylinders for which the height and radius are the same value. Let
VashaNatasha [74]

Answer:

Relation between V and c is represented as:

V = \pi c^{3}

When c is halved, V becomes \frac{1}{8} of its initial value.

Step-by-step explanation:

Height of cylinder = Radius of cylinder = c

Volume of cylinder = V

As per formula:

V = \pi r^{2} h

Where r is the radius of cylinder and

h is the height of cylinder

Putting r = h =c

V = \pi c^{2} \times c\\\Rightarrow V = \pi c^{3} ......(1)

The values of c is halved:

Using equation (1), New volume:

V' = \pi (\dfrac{c}{2})^3\\\Rightarrow \dfrac{1}{8} \pi c^{3}

By equation (1), putting \pi \times c^{3}  = V

V' = \dfrac{1}{8} \times V

So, when c is halved, V becomes \frac{1}{8} of its initial value.

3 0
2 years ago
Does 23^-1 (mod 1000) exist? If yes solve it.
sweet [91]

Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).

Let <em>x</em> be the inverse. Then <em>x</em> is such that

23<em>x</em> ≡ 1 (mod 1000)

Use the Euclidean algorithm to solve for <em>x</em> :

1000 = 43×23 + 11

23 = 2×11 + 1

→   1 ≡ 23 - 2×11   (mod 1000)

→   1 ≡ 23 - 2×(1000 - 43×23)   (mod 1000)

→   1 ≡ 23 - 2×1000 + 86×23   (mod 1000)

→   1 ≡ 87×23 - 2×1000 ≡ 87×23   (mod 1000)

→   23⁻¹ ≡ 87   (mod 1000)

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Nataly_w [17]

s1+s2>s3  where s1 and s2 are the 2 smaller sides

Choice C is the only 1 that fits

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