Question

the position of a submarine relative to the water surface was -32 1/4 feet . A downward navigational manuever increased it's depth by 15 1/2 feet. What is the position of the submarine now relative to the water surface?

Answer 1

Answer:

Position of the submarine now relative to the water surface $=-47\ \frac{3}{4}$

Step-by-step explanation:

It says that the position of a submarine relative to the water surface was -32 1/4 feet . A downward navigational maneuver increased it's depth by 15 1/2 feet.

Now we need to find about what is the position of the submarine now relative to the water surface.

Downward navigation means we 15 1/2 is negative

so we will just add both values to get the final answer:

Position of the submarine now relative to the water surface = $-32\ \frac{1}{4}-15\ \frac{1}{2}$

$=-32\ \frac{1}{4}-15\ \frac{2}{4}$

$=-47\ \frac{3}{4}$