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Simora [160]
3 years ago
14

HELP !!!! can someone help me please how can i use the vertex formula to find this equation for this graph ?

Mathematics
1 answer:
DedPeter [7]3 years ago
5 0
Based on that table of values, we know the highest point(vertex) is at 0.9, 5.9

we can also use just one another point... say 1.4, 4.6

\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
y=a(x-{{ h}})^2+{{ k}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\

\bf \begin{cases}
h=0.9\\
k=5.9
\end{cases}\implies y=a(x-0.9)^2+5.9
\\\\\\
\begin{cases}
\textit{another point}\\
x=1.4\\
y=4.6
\end{cases}\implies 4.6=a(1.4-0.9)^2+5.9
\\\\\\
4.6=a(0.5)^2+5.9\implies 4.6-5.9=a(0.5)^2\implies -1.3=a(0.5)^2
\\\\\\
\cfrac{-1.3}{0.5^2}=a\implies -5.2=a
\\\\\\
thus\qquad \qquad \boxed{y=-5.2(x-0.9)^2+5.9}
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3x+5y=4, 2x-y=-7 solve using substitution
victus00 [196]
 <span>3x+5y=4...(1)
 2x-y=-7...(2)
by(2) : y = 2x+7
subsct in (1) : 
3x +5(2x+7) = 4 
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x = -31/13
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3 years ago
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Archy [21]

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Step-by-step explanation:

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8 0
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Read 2 more answers
Find the quotient and any excluded values.<br><br> (x + 5/x^2 + 9x + 20)/(x^2-16/x-4)
Wittaler [7]
By  <span>(x + 5/x^2 + 9x + 20) you apparently meant the following:

         x+5
 ----------------------
   x^2 + 9x + 20

and by 

</span><span>(x^2-16/x-4)
                                       x^2-16
you apparently meant ---------------
                                         x - 4

Please use additional parentheses for clarity.

Dividing,

</span>         x+5                   (x-4)(x+4)
 ----------------------  *  ---------------
   x^2 + 9x + 20                  x-4

Now, x^2 + 9x + 20 factors into   (x+4)(x+5), so what we have now is

       (x+5)(x+4)
------------------------- = 1           This is true for all x, so there are no exclusions.
    (x+4)(x+5)
3 0
3 years ago
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