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Simora [160]
3 years ago
14

HELP !!!! can someone help me please how can i use the vertex formula to find this equation for this graph ?

Mathematics
1 answer:
DedPeter [7]3 years ago
5 0
Based on that table of values, we know the highest point(vertex) is at 0.9, 5.9

we can also use just one another point... say 1.4, 4.6

\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
y=a(x-{{ h}})^2+{{ k}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\

\bf \begin{cases}
h=0.9\\
k=5.9
\end{cases}\implies y=a(x-0.9)^2+5.9
\\\\\\
\begin{cases}
\textit{another point}\\
x=1.4\\
y=4.6
\end{cases}\implies 4.6=a(1.4-0.9)^2+5.9
\\\\\\
4.6=a(0.5)^2+5.9\implies 4.6-5.9=a(0.5)^2\implies -1.3=a(0.5)^2
\\\\\\
\cfrac{-1.3}{0.5^2}=a\implies -5.2=a
\\\\\\
thus\qquad \qquad \boxed{y=-5.2(x-0.9)^2+5.9}
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ANSWER

The three expressions are

V = 2(9 - {b}^{3} )(9 + {b}^{3} )

EXPLANATION

We were given the volume in cubic units to

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If we factor 2, we get,

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The expression in parenthesis is a difference of two squares. But you may not recognize it at first sight.

V = 2( {9}^{2} - ({b}^{3})^{2} )

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