The summand (R?) is missing, but we can always come up with another one.
Divide the interval [0, 1] into 
subintervals of equal length 
:
![[0,1]=\left[0,\dfrac1n\right]\cup\left[\dfrac1n,\dfrac2n\right]\cup\cdots\cup\left[1-\dfrac1n,1\right]](https://tex.z-dn.net/?f=%5B0%2C1%5D%3D%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%5Ccup%5Ccdots%5Ccup%5Cleft%5B1-%5Cdfrac1n%2C1%5Cright%5D)
Let's consider a left-endpoint sum, so that we take values of 
where 
is given by the sequence
with 
. Then the definite integral is equal to the Riemann sum
Answer:
answer is d.-3/2x +5
Step-by-step explanation:
this was tough but I did it. First you multiply all the terms with 1/4. Then just simplify the terms by breaking them down and then apply normal addition and subtraction. Simple. Thank you
Bff i answered this earlier. It’s step 2!!! Because if you’re flipping the numerator and denominator, the sign of the exponent should be flipped as well. So the exponent will turn into -5x
Sorry if my previous answer was vague. #brainliest!!!
The correct answer is, obviously, 34/7.
If $1.60 is 1 pound, divide the $ amount by 1.60 to find the number of pounds. 150/1.6 = 93.75
