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drek231 [11]
3 years ago
7

Is a square always a quadrilateral

Mathematics
2 answers:
Illusion [34]3 years ago
6 0
Yes but a quadrilateral isnt always a square

ad-work [718]3 years ago
3 0

Answer:

yes a square is always a quadrilateral

Step-by-step explanation:

but i kite is not always a square

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I give 20! Find the surface area. And without explanation please, I don’t have enough time.
oee [108]

Answer:

816 cm²

Step-by-step explanation:

Surface area of the composite figure = (surface area of the larger rectangular prism + surface area of the smaller rectangular prism) - area of the side of the smaller rectangular prism that is joined to the bigger prism.

✔️Surface area of the larger rectangular prism:

Area = L*W*H = 20*5*6 = 600 cm²

✔️surface area of the smaller rectangular prism:

Area = L*W*H = 12*4*6 = 288 cm²

✔️area of the side of the smaller rectangular prism that is joined to the bigger prism.

Area = L*W = 12*6 = 72 cm²

Surface area of the composite = (600 + 288) - 72 = 888 - 72 = 816 cm².

8 0
3 years ago
What is 5 divided by 2
vodka [1.7K]
5 divides by 2 is 2.5 I hope that hekos
5 0
4 years ago
Read 2 more answers
An oblique hexagonal prism has a base area of 42
AlekseyPX

Answer:

168 cm³

Step-by-step explanation:

The base area of the oblique hexagonal prism = 42 cm²

the height of the prism = 4 cm

Volume of the prism = Base area × height = 42 cm² × 4 cm = 168 cm³

7 0
3 years ago
Could 13 15 and 19 be a right triangle
Nat2105 [25]

Answer:

No b/c the hypotenuse is too short

Step-by-step explanation:

13² + 15² = 19²

169 + 225 = 361

394 ≠ 361

6 0
3 years ago
Help i'll make you the brainliest
9966 [12]

Answer:

D) b = \frac{S-2ac}{2a + 2c}

Step-by-step explanation:

First, move all the terms that do not include b to the left side with S:

S = 2ab + 2bc + 2ac

S - 2ac = 2ab + 2bc

Now, factor out 2b from the right side:

S - 2ac = 2b(a + c)

Divide both sides by 2(a + c):

b = \frac{S-2ac}{2(a + c)}

Finally, multiply out the denominator:

b = \frac{S-2ac}{2a + 2c}

7 0
3 years ago
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