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Neporo4naja [7]
2 years ago
5

A positive number is called $n$-primable if it is divisible by $n$ and each of its digits is a one-digit prime number. How many

3-primable positive integers are there that are less than 1000
Mathematics
1 answer:
boyakko [2]2 years ago
4 0
Single digit primes are 2, 3, 5 and 7. Only 3 is 3-primable
Two digit numbers that are 3-primable are
27, 33, 57, 72, 75
The 3 digit numbers that are 3-primable are
222, 333, 555, 777
225, 252, 522
237, 273, 327, 372, 723, 732
255, 525, 552
357, 375, 537, 573, 735, 753

There are 28 3-primable natural numbers less than 1000
You might be interested in
Anyone help me !!!!!!!!!!!
astra-53 [7]

Answer:

idk the first 2 but the 3rd one is QR and QT

Step-by-step explanation:

those are the lines on either side of 1.

3 0
3 years ago
What does y equal?<br>6=2(y+2)<br>Thank you!
egoroff_w [7]
6=2y+4
y is equal to 1
7 0
3 years ago
There are 65 children in the sixth grade. The ratio of boys to girls 3 to 2. A) how many girls are in the grade?
Akimi4 [234]

Given that,

Total number of children = 65

The ratio of boys to girls is 3 :2.

To find,

The number of girls in the grade.

Solution,

Let there are 3x girls and 2x boys.

ATQ,

3x + 2x = 65

5x = 65

x = 13

So, no of girls = 3x

= 3(13)

= 39

Hence, there are 39 girls in the grade.

5 0
3 years ago
This is the table i need help with
Papessa [141]
2.3 is the other length
Hope this helps :)
8 0
2 years ago
Read 2 more answers
Please help me with this
xenn [34]

Step-by-step explanation:

based on my understanding of the dreidel, this is a regular spinner with 4 equal sides (but different symbols on them, so, we can clearly distinguish between the possible 4 different outcomes).

in other words, this resembles a die with only 4 sides and therefore only 4 equally probable outcomes.

and therefore, the probability to get the specified symbol in 1 attempt is indeed 1/4.

remember, a probability is always desired cases over totally possible cases.

and here, we have one desired outcome out of 4 possible outcomes. hence the probability of 1/4.

now, we are spinning the dreidel twice.

that means we have now 4×4 = 16 possible outcomes.

but we only want the outcomes, where the specified symbol is showing exactly once - either after the first spin or after the second spin.

so, out of the 16 possible combinations, we want only the ones, where the first spin delivered that result :

1 option on the first spin and 3 options (4 minus the already delivered result) on the second spin : 1×3 = 3.

and the ones, where the second spin delivered the result (but not the first). so, we have 3×1 = 3 options there.

that means we have 6 desired cases out of total 16 possible outcomes, and the probability is

6/16 = 3/8

mathematically we would simply say that the probability is the sum of

the probability of spinning it first combined with the probability of not spinning it second.

the probability of not spinning it first combined with the probability to spin it second.

that is

1/4 × 3/4 = 3/16

+

3/4 × 1/4 = 3/16

-----------------------

6/16 = 3/8

I don't know the options you can select, but I hope you understand the principles I explained. and I gave you the result and the way to calculate it.

so, hopefully you find the fitting options.

8 0
2 years ago
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