How do you do this to get one pls I need help

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 89m long and 70m wide.

Sindrei [870]

Step One

Find the area of the rectangle

Area = L * W

Area = 89 cm * 70 cm

Area = 6230 cm^2

Step Two

What is the formula for the two end semicircles?

Two semicircles = 1 whole circle

Area of any circle = pi * r^2

Step Three

Find the area of the circle

r = the width / 2 This may not be true. You need the diagram. If the circles are drawn on the length then use r = the length / 2

r = 70/2 = 35 cm

Area of circle = pi * r^2

Area of circle = 3.14 * 35^2

Area of circle = 3846.5

Step Four

Find the total area

The total area = Area of the rectangle + area of circle

The total area = 6230 + 3846.5

The total area = 10076.5 cm^2 <<<< Answer

3 0

3 years ago

19, 38, 76, ... find the 8th term

Alisiya [41]

I think it’s 557

reasoning in pic

4 0

2 years ago

What is the value of x three times less than the value of 45−10x?

Mekhanik [1.2K]

This is the concept of algebra. The value of x three times less than the value of 45-10x will be as follows;
The value of x three times is:
3x
subtracting 45-10x we get:
3x-(45-10x)
3x+10x-45
13x-45
the answer is:
13x-45

6 0

3 years ago

Math question down below

Sholpan [36]

5(x + 30)

x + 30 represents the number of minutes per day he practices
5 is the number of days he practices
so 5(x+30) = the total number of minutes he practices in 5 days

For example, if he practices the piano for 20 minutes per day and the violin for 30 minutes per day, he practices a total of 50 minutes per day. For 5 days that would be 5 x 50 = 250 minutes in 5 days.

Plug that into the equation
5(x+30) = 5(20+30) = 5(50) = 250

5 0

3 years ago

Read 2 more answers

Somebody please help so I can pass, please

ASHA 777 [7]

First, we are going to find the vertex of our quadratic. Remember that to find the vertex $(h,k)$ of a quadratic equation of the form $y=a x^{2} +bx+c$ , we use the vertex formula $h= \frac{-b}{2a}$ , and then, we evaluate our equation at $h$ to find $k$ .

We now from our quadratic that $a=2$ and $b=-32$ , so lets use our formula:
$h= \frac{-b}{2a}$
$h= \frac{-(-32)}{2(2)}$
$h= \frac{32}{4}$
$h=8$
Now we can evaluate our quadratic at 8 to find $k$ :
$k=2(8)^2-32(8)+56$
$k=2(64)-256+56$
$k=128-200$
$k=-72$
So the vertex of our function is (8,-72)

Next, we are going to use the vertex to rewrite our quadratic equation:
$y=a(x-h)^2+k$
$y=2(x-8)^2+(-72)$
$y=2(x-8)^2-72$
The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.

We can conclude that:
The rewritten equation is $y=2(x-8)^2-72$
The x-coordinate of the minimum is 8

8 0

3 years ago

Read 2 more answers