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Lena [83]
3 years ago
6

Please help!!! 15 points problem below

Mathematics
1 answer:
MissTica3 years ago
5 0

We are given height function of the bridge

h(x) =-0.5(x-4)^2 +2.

Where height is the height of the bridge in feet and x is the distance between two bases.

We have height =0 on the base of the bridge. In order to find the both bases, we need to plug h(x) as 0 and solve for x.

-0.5(x-4)^2 +2 = 0

\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}

-0.5\left(x-4\right)^2+2-2=0-2

-0.5\left(x-4\right)^2=-2

\mathrm{Multiply\:both\:sides\:by\:}10

-0.5\left(x-4\right)^2\cdot \:10=-2\cdot \:10

-5\left(x-4\right)^2=-20

\mathrm{Divide\:both\:sides\:by\:}-5

\frac{-5\left(x-4\right)^2}{-5}=\frac{-20}{-5}

\left(x-4\right)^2=4

Taking square root on both sides, we get

x-4=\sqrt{4}

\:x-4=\sqrt{4} \ and \ x-4=-\sqrt{4}

x-4=2 \\x-4=-2

x=6,\:x=2

We got horizontal distances 2 feet and 6 feet.

Therefore, correct option is D.

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Answer:

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Step-by-step explanation:

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The exponential function is given in the form

y= a (b)^{x}

where a is the initial value and b is the multiplicative rate of change

When  x=1, y=9, we have:

9= a (b)^{1}

When  x=3, y=4, we have:

4= a (b)^{3}

Dividing the two equations:

\dfrac{a (b)^{3}}{a (b)^{1}} =\dfrac{4}{9} \\b^2=\dfrac{4}{9}\\b=\sqrt{\dfrac{4}{9}} \\b=\dfrac{2}{3}

The multiplicative rate of change, b is 2/3.

5 0
3 years ago
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Maru [420]

Answer:

\frac{2}{\sqrt{2} } = \sqrt{2}

Step-by-step explanation:

Notice from the attached image that -315 degrees is the same as 45 degrees.

Recall as well that the csc function is defined as the reciprocal of the sine function: csc(x)=\frac{1}{sin(x)}

Then, you need to evaluate \frac{1}{sin(45)} = 1/\frac{\sqrt{2} }{2} = \frac{2}{\sqrt{2} } =\sqrt{2}

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If h(x) = 6 – x, what is the value of (hxh) (10)
vova2212 [387]

For those who may need it in the future, the answer on e1010 is actually: C: 10

8 0
3 years ago
Find AB distance. Please help
Svet_ta [14]

Answer:

Solution,

Let,(x1,y1)=(-4,-3)

     (x2,y2)=(3,5)

Using distance formula,

AB=√(x2-x1)²+(y2-y1)²

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Step-by-step explanation:

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3 years ago
An airplane is preparing to land at an airport. It is 50400 feet above the ground and is descending at the rate of 3000 feet per
Dovator [93]

Answer:

let t = no of minutes when they are at the same altitude

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52200 - 3300t = 2500t

52200 = 3300t + 2500t

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t = 52200/5800

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The altitude:

9*2500 = 22500 ft

:

Check on other train

52200 - 9(3300) =

52200 - 29700 = 22500 ft

3 0
2 years ago
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