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nekit [7.7K]
3 years ago
11

Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor

dinate plane as kites BRAD and KELY, respectively:
Which statement is correct about the two kites?
A. They are similar because BR : DB is 1 : 3 and KE : YK is 1 : 3
B. They are similar because BR : DB is 1 : 2 and KE : YK is 1 : 2
C. They are not similar because BR : DB is 1 : 2 and KE : YK is 1 : 3
D. They are not similar because BR : DB is 1 : 3 and KE : YK is 1 : 2

Mathematics
2 answers:
Reptile [31]3 years ago
8 0

The answer I am going with is between A and D but I mainly go with D. I hope this works


GalinKa [24]3 years ago
7 0

Answer:  They are not similar because BR : DB is 1:2 and KE :YK is 1:3. I just took the test, good luck hope you get a good score.


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I got the same answer as the example
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3 years ago
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Yuki888 [10]

Solving for <em>Angles</em>

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* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

Solving for <em>Edges</em>

\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2

You would use this law under <em>two</em> conditions:

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  • ALL three edges defined

* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:

  • Two angles and one edge defined, while trying to solve for the <em>second edge</em>
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* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0
2 years ago
What is the value of "c" in the quadratic equation 3x 2 + 5x + 7 = 0?<br><br> 3<br> 5<br> 7
dmitriy555 [2]

Answer:

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Step-by-step explanation:

They are just asking you to compare

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What constant values are in the place of a,b, \text{ and } c.

a=3

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c=7

7 0
3 years ago
Read 2 more answers
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