Answer:
<em>f(x) = x² (2+i)x-15-3i</em>
Step-by-step explanation:
Since the zeros of the equation are -3 and 5+i, hence the factors of the polynomial in x is (x+3) and (x-(5+i))
Multiplying both factors
f(x) = (x+3)(x-(5+i))
f(x) = (x²-(5+i)x+3x -3(5+i))
f(x) = x² - (5+i- 3)x -15-3i
f(x) = x² (2+i)x-15-3i
<em>hence the required polynomial function in x is f(x) = x² (2+i)x-15-3i</em>
Whats the question??????????????????????
The midpoint formula is:
(point1 + point2)/2
1) (-2 + 12)/2 = 5
2) (-1 +5)/2 = 2
(0+2)/2 = 1
(2,1)
3) Sqrt of (x2-x1)^2 + (y2 - y1)^2
sqrt of (7 -1)^2 + (-7 - 1)^2
sqrt of (6)^2 + (-8)^2
sqrt of 36 + 64
sqrt of 100
10
Hope this helps!
19, 36, 23, 42, 21, 33, 23, 24, 36, 42, 23, 37, 37, 33, 17
LekaFEV [45]
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