All categories

3 years ago

Plot these coordinates and determine the resulting figure.

Mathematics

1 answer:

Artyom0805 [142]3 years ago

6 0

Answer:

The answer is C. line

Step-by-step explanation:

You might be interested in

4. In an electrical circuit it is known that the voltage V varies as the current I

SSSSS [86.1K]

Step-by-step explanation:

V∝I

V=kI

36=k*8

k=36/8

k=4.5

a. V=4.5I

b. V=4.5*14

V= 63

c. 27=4.5I

I=27/4.5

I= 6

8 0

2 years ago

What is the equation of the following line??

wolverine [178]

Answer:

C) y = 6x is the answer.

Step-by-step explanation:

(-1/2,-3) and (0,0)

slope(m) = ( 0 + 3)/(0 + 1/2)= 3/1/2 = 6

Now,

y = mx + b

or, y = 6x + 0

so, y = 6x

5 0

2 years ago

If Susan is 4 feet 8 inches tall and Sharon is 5 feet 4 inches tall, what is the ratio of Sharon’s height to Susan’s height?

poizon [28]

64:56 turns into 8:7.

4 0

3 years ago

Someone help me please

Damm [24]

Should be A. 12.3x12.3 is about 6x25

6 0

2 years ago

Indefinite integral need help pleaseeeeeee

tatiyna

Integrate indefinite integral:
$I=\int\frac{dx}{e^{2x}+3e^x+2}dx$

Solution:
1. use substitution $u=e^x$
=>
$du=e^xdx$
=>
$dx=\frac{du}{e^x}$
=>
$dx=\frac{du}{u}$
=>
$I=\int\frac{du}{u(u^2+3u+2)}du$
$=\int\frac{du}{u(u+2)(u+1)}du$
2. decompose into partial fractions
$\frac{1}{u(u+2)(u+1)}$
$=\frac{A}{u}+\frac{B}{u+2}+\frac{C}{u+1}$
where A=1/2, B=1/2, C=-1
$=\frac{1}{2u}+\frac{1}{2(u+2)}-\frac{1}{u+1}$
3. Substitute partial fractions and continue
$I=\int\frac{du}{2u}+\int\frac{du}{2(u+2)}-\int\frac{du}{u+1}$
$=\frac{log(u)}{2}+\frac{log(u+2)}{2}-log(u+1)}$
4. back-substitute u=e^x
$=\frac{log(e^x)}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}$
$=\frac{x}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}$

Note: log(x) stands for natural log, and NOT log10(x)

7 0

2 years ago