Answer:
<h2>Hyy There !! </h2>
Step-by-step explanation:
<h3><u>Question Says :- </u></h3>
• The Area of a sector when r = 9/2 and
θ = 5pi/6 radians ? .
? pi / ?
<h3><u>Circular Area of a Sector</u></h3>
Problems involving area of a sector can be solved easily. One should just obtain two essential information from the circle of interest, the central angle measure θ and radius r For angle measures in radians, the area A is calculated as :-
<h3>A = 1/2r^2θ. </h3>
<h3>Hope this helps you !! </h3>
- 5 + 5x = - 1 + 6x
- 5 + 5 + 5x = - 1 + 5 + 6x
5x = 4 + 6x
5x - 6x = 6x - 6x + 4
- x = 4
x = - 4
Answer:
x<5
Step-by-step explanation:
the greater sign will firstly be changed to = for better solving so we obtain
3+9x=4(x+7)by opening bracket
3+9x=4x+28
9x-4x=28-3
5x=25
divide all through by 5x
we obtain
x=5
the greater sign change here
which is x<5
2) 1 4/5
3) 2
4) 4 1/3
5) 3 4/8 or 3 1/2
6) 6 2/8
