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VladimirAG [237]

3 years ago

5

Martha estimated there were 90 marbles in a jar for a contest. The actual number of marbles in the jar was 112. What was the per

cent error of Martha's estimation?

2 answers:

lbvjy [14]3 years ago

6 0

22% I hope it helps you I'm not positive I'm not the best but she was 22 numbers away from getting it right so

irinina [24]3 years ago

5 0

Answer:

my dudes it is 19.64%

B)

Step-by-step explanation:

You might be interested in

If f(x) = -3x - 5 and g(x) = 4x - 2, find (f - g)(x).

ratelena [41]

Answer:

A. (f-g)(x) = -7x -3

Step-by-step explanation:

(f -g)(x) = f(x) -g(x) = (-3x -5) -(4x -2)

= -3x -5 -4x +2

= -3x -4x -5 +2

(f -g)(x) = -7x -3

3 0

2 years ago

Help !! Pleaseeeeeeeee

marysya [2.9K]

Answer:

Step-by-step explanation:

arc BE is the same as the interior angle, or 76°

BE = 76 °

we can also find arc CE the same way, b/c we can see that the interior angle is the suppment with 76 or 180-76 = CE or 104°

Now we know all the arcs but arc CD

so use the idea that all the way around the circle is 360°

360 = 76 + 104 + 140 + CD

360 - 76 - 104 - 140 = CD

40 = CD

CD = 40 °

7 0

3 years ago

A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

$Width = 3 - 2x \\\\$

The length of the shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\$

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$

Volume of the box at x= 1.59:

$V = \frac{1}{2} (5 – 3(1.59)) \times (3 - 2(1.59)) \times (1.59) \\\\V = -0.03 \: cm^3 \\\\$

Volume of the box at x= 0.53:

$V = \frac{1}{2} (5 – 3(0.53)) \times (3 - 2(0.53)) \times (0.53) \\\\V = 1.75 \: cm^3$

The volume of the box is maximized when x = 0.53 cm

Therefore,

x = 0.53 cm

Maximum volume = 1.75 cm³

7 0

3 years ago

Select the correct answer.

torisob [31]

Answer:

C. - f(x) = f( - x)

Step-by-step explanation:

<u>Property of the odd function is:</u>

- f(x) = f( - x)

<u>Same applies to the given function:</u>

f(x) = -2x⁵ + x³ - 7x
f(- x) = -2(-x)⁵ + (- x)³ - 7(-x) = 2x⁵ - x³ + 7x = - (2x⁵ + x³ - 7x) = - f(x)

4 0

3 years ago

Simplify the expression in exponential notation.<br><br> a • a • a

vladimir2022 [97]

the answer would be a³

8 0

3 years ago

Read 2 more answers